c - 尝试打印 char* 的内容时出现段错误

Question

我有以下代码:

    FILE *fpa;
    fpa = fopen(argv[2], "r");
    if (fpa == NULL) {
     printf("Error: could not open seqA file!\n");
     exit(0);
    }

    unsigned int N_a;
    fscanf(fpa, "%d\n", &N_a);
    char *seq_a = malloc((N_a+1) * sizeof(char *));
    strcpy(seq_a,"");
    fscanf(fpa, "%s\n", seq_a);
    fclose(fpa);

    for(i=0;i<N_a;i++)
      printf("%s", seq_a[i]); ---> SEG FAULT
    printf("\n");

我在 printf 语句中遇到段错误。argv[2] 是一个文件，其内容为:
5
ABCBB

知道我可能在哪里犯错误。

Answer 1

char *seq_a = malloc((N_a+1) * sizeof(char *));

应该是:char *seq_a = malloc((N_a+1) * sizeof(char));

如果您想打印每个字符，请使用%c:

  printf("%c", seq_a[i]);