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c - 程序不会打印 txt 文件中的所有行

转载 作者:行者123 更新时间:2023-11-30 15:53:35 26 4
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写了这个程序,应该能够打印出txt文件中的所有行,但它只打印一行,现在已经看了1个小时了,我找不到错误,任何帮助都会得到帮助! :)

1 2011 年 7 月 16 日17.00 OB - FCN 2 - 0 6.965
1 2011 年 7 月 17 日14.00 FCM - SIF 1 - 2 5.370
1 2011 年 7 月 17 日16.00 ACH - HBK 3 - 0 2.227
1 2011 年 7 月 17 日16.00 SDR - FCK 0 - 2 4.992
前 4 行。

#include <stdio.h>
#include <stdlib.h>
#define MAX_LINE_LGT 200
#define NAME_MAX 200
#define TEAM_MAX 200

struct team{
char name[NAME_MAX];
int five_or_more_goals;
};
typedef struct team team;

void read_data_1(const char *file_name, team teams[]){
FILE *ifp;
char team1[NAME_MAX];
char team2[NAME_MAX];
int goal1, goal2;
int dag, month, year;
double clock;
int attendance;
int round;
team local_match;

ifp = fopen(file_name, "r");

while (fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %d\n", &round, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10){
printf("runde %d den %d %d %d klokken %.2lf, mellem %s og %s endte %d - %d %d så kampen\n", round, dag, month, year, clock, team1, team2, goal1, goal2, attendance);
}

fclose(ifp);

}

int main(void) {
team all_matches_teams[TEAM_MAX];
read_data_1("superliga-2011-2012", all_matches_teams);

return 0;
}

最佳答案

您在每行输入末尾的出勤值导致了您的问题。您需要将其解析为 float 或用句点分隔的两个小数,而不仅仅是一个小数。假设出席人数永远不会达到一百万,它应该可以与下面的代码更改一起使用:

int valuesRead;
int attendance;
int attend1, attend2;
[...]
while ((valuesRead = fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %d.%d\n", &round, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attend1, &attend2)) >= 10){
if (valuesRead == 11)
attendance = attend1 * 1000 + attend2;
else
attendance = attend1;
printf("runde %d den %d %d %d klokken %.2lf, mellem %s og %s endte %d - %d %d så kampen\n", round, dag, month, year, clock, team1, team2, goal1, goal2, attendance);
}

关于c - 程序不会打印 txt 文件中的所有行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13552698/

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