c - 响应某些命令的 Sketch 是如何完成的？

Question

好吧，我现在有一个半完整的 Arduino 草图。基本上，如果一串字符等于 *{blink_Flow_A}*，下面的草图将使 kegboard-mini 扩展板上的 LED 闪烁，但是，在 Arduino 上加载当前草图时，LED 仅闪烁一次。我希望 Arduino 反复闪烁，直到“停止”命令发送到 Arduino。我最终想打开一个阀门，保持打开状态，直到阀门收到关闭命令，然后关闭阀门。草图如下所示，

/*
 * kegboard-serial-simple-blink07
 * This code is public domain
 *
 * This sketch sends a receives a multibyte String from the iPhone
 * and performs functions on it.
 *
 * Examples:
 * http://arduino.cc/en/Tutorial/SerialEvent
 * http://arduino.cc/en/Serial/read
 */

 // global variables should be identified with _

 // flow_A LED
 int led = 4;

 // relay_A
 const int RELAY_A = A0;

 // variables from sketch example
 String inputString = ""; // a string to hold incoming data
 boolean stringComplete = false; // whether the string is complete

 void setup() {

   Serial.begin(2400); // open serial port, sets data rate to 2400bps
   Serial.println("Power on test");
   inputString.reserve(200);

   pinMode(RELAY_A, OUTPUT);
}

void open_valve() {

  digitalWrite(RELAY_A, HIGH); // turn RELAY_A on

}

void close_valve() {

  digitalWrite(RELAY_A, LOW); // turn RELAY_A off
}

void flow_A_blink() {

  digitalWrite(led, HIGH); // turn the LED on (HIGH is the voltage level)
  delay(1000);              // wait for one second
  digitalWrite(led, LOW);   // turn the LED off by making the voltage LOW
  delay(1000);              // wait for a second
}

void flow_A_blink_stop() {

  digitalWrite(led, LOW);
}

void loop() {
  // print the string when newline arrives:
  if (stringComplete) {
    Serial.println(inputString);
    // clear the string:
    inputString = "";
    stringComplete = false;
  }

  if (inputString == "{blink_Flow_A}") {
    flow_A_blink();
  }
}

//SerialEvent occurs whenever a new data comes in the
//hardware serial RX.  This routine is run between each
//time loop() runs, so using delay inside loop can delay
//response.  Multiple bytes of data may be available.

void serialEvent() {
  while(Serial.available()) {
    // get the new byte:
    char inChar = (char)Serial.read();
    // add it to the inputString:
    inputString += inChar;
    // if the incoming character is a newline, set a flag
    // so the main loop can do something about it:
    if (inChar == '\n') {
      stringComplete = true;
    }
  }
}

如果这有什么不同的话，IRC 上有人告诉我研究状态机挠头

Answer 1

要使 Led 闪烁而不阻塞程序，我建议您使用计时器(和 TimerOne library )。我制作了一个快速示例代码:

#include "TimerOne.h" //Include the librart, follow the previous link to download and install.

int LED = 4;
const int RELAY_A = A0;  
boolean ledOn;

void setup()
{
    pinMode(LED, OUTPUT)
    Timer1.initialise(500000) // Initialise timer1 with a 1/2 second (500000µs) period
    ledOn = false;
}

void blinkCallback() // Callback function call every 1/2 second when attached to the timer
{
    if(ledOn){
        digitalWrite(LED,LOW);
        ledOn = false;
    }
    else{
        digitalWrite(LED,HIGH);     
        ledOn = true;
    }
}

void open_valve() {

  digitalWrite(RELAY_A, HIGH); // turn RELAY_A on

}

void close_valve() {

  digitalWrite(RELAY_A, LOW); // turn RELAY_A off
}

void serialEvent() {
  while(Serial.available()) {
    char inChar = (char)Serial.read();
    inputString += inChar;
    if (inChar == '\n') {
      stringComplete = true;
    }
  }
}

void loop()
{
    // print the string when newline arrives:
  if (stringComplete) {
    Serial.println(inputString);
    // clear the string:
    inputString = "";
    stringComplete = false;
  }


  if (inputString == "{blink_Flow_A}") {
    Timer1.attachInterupt(blinkCallback); //Start blinking
  }
  if (inputString == "{stop}") {
    Timer1.detachInterrupt(); //Stop blinking
  }
  if (inputString == "{open_valve}") {
    open_valve();
  }
  if (inputString == "{close_valve}") {
    close_valve();
  }
}  

注意:
考虑放置标签“c”或“java”以在代码上进行语法突出显示。