C - 从区间打印随机数

Question

这是我的代码，我需要它首先说出 1-10 数字的数量，然后打印它们是哪些。它得到了正确的数字，但不是打印等于 1-10 的数字，而是打印前 10 个数字。

#include <time.h> 
#include <stdlib.h> 
#include <stdio.h>
int main () {
    int i;
    int br = 0, brr = 0, brrr = 0, br1 = 0;
    int polje[50];
    srand(time(NULL));
    for(i = 0; i < 50; i++) {
        polje[i] = rand() % 30 + 1;
        printf("%d ", polje[i]);
    }
    printf("\n");
    for(i = 0; i < 50; i++) {
        if(polje[i] >= 1 && polje[i] <= 10)
            br++;
    }
    printf("Brojevi od 1 do 10 pojavljuju se %d puta a to su ", br);

    do {
        for(i = 0; i < 10; i++)
            printf("%d ", polje[i]);

    } while (polje[i] >= 1 && polje[i] <= 10);

    return 0;
}

Answer 1

... and then print which ones they are

如果您需要按照 polje 数组中出现的顺序打印数字:

#include <time.h>
#include <stdlib.h> 
#include <stdio.h>
int main () {
    int i;
    int br = 0, brr = 0, brrr = 0, br1 = 0;
    int polje[50];
    srand(time(NULL));
    for(i = 0; i < 50; i++) {
        polje[i] = rand() % 30 + 1;
        printf("%d ", polje[i]);
    }
    printf("\n");
    for(i = 0; i < 50; i++) {
        if(polje[i] >= 1 && polje[i] <= 10)
            br++;
    }
    printf("Brojevi od 1 do 10 pojavljuju se %d puta a to su ", br);

    // changed from here:
    for(i = 0; i < 50; i++) {
        if(polje[i] >= 1 && polje[i] <= 10)
            printf( "%d ", polje[i] );
    }

    return 0;
}

如果您需要在 polje 数组中打印它们的索引(位置):

#include <time.h> 
#include <stdlib.h> 
#include <stdio.h>
int main () {
    int i;
    int br = 0, brr = 0, brrr = 0, br1 = 0;
    int polje[50];
    srand(time(NULL));
    for(i = 0; i < 50; i++) {
        polje[i] = rand() % 30 + 1;
        printf("%d ", polje[i]);
    }
    printf("\n");
    for(i = 0; i < 50; i++) {
        if(polje[i] >= 1 && polje[i] <= 10)
            br++;
    }
    printf("Brojevi od 1 do 10 pojavljuju se %d puta a to su ", br);

    // changed from here:
    for(i = 0; i < 50; i++) {
        if(polje[i] >= 1 && polje[i] <= 10)
            printf( "%d ", i );
    }

    return 0;
}