检查 ISBN 以查看其在 C 语言中是否有效

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已关闭。这个问题是 not reproducible or was caused by typos 。目前不接受答案。

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我正在尝试检查 ISBN 在 C 中是否有效。我想忽略任何非整数的数组值，例如忽略 - 或空格。我收到以下代码部分的错误:

if(s[jj] == '-' || size[jj] == ' ') 

错误信息如下:

error: subscripted value is neither array nor pointer

int checkISBN( char s[] ) {
        int result = 0;  
        int theSize = 18;  /* Most ISBNs are 10 digits long, with some being 
                            * 13. I just chose 18 incase there are a lot of 
                            * blank spaces or dashes in the array. */
        int n = 1;         /* This comes in handy for determing if the check 
                              character is valid. */
        int sum = 0;       /* We divide this value by 11 to determine if the 
                              check character is valid */
        int jj;

        for (jj = 0; jj sum += s[i] * n; ++n;
                /* For the below, the formula works like this: 
                 * The sum for the ISBN 0-8065-0959-7 is

                   1*0 + 2*8 + 3*0 + 4*6 + 5*5 + 6*0 + 7*9 + 8*5 + 9*9 = 249

                 * The remainder when 249 is divided by 11 is 7, the last 
                 * character in the ISBN. The check character is used to 
                 * validate an ISBN. 
                 * */
        ...
}

...

int checkCharacter = sum / 11; 

if (checkCharacter == s[size-1]) { 
        result = 1;
        /* I know this part is wrong. 
        * If the array only contains 10 values, then s[17] will be null. 
        * I'll fix this later.
        * */
        return result;;
        /* Fix this to return a calculated value based on string */
}

Answer 1

简单的拼写错误，size 不是数组。应该是:

if(s[jj] == '-' || s[jj] == ' ')
                  ^^^