C 编程。代码错误不允许我进入下一个函数

Question

以下代码是我正在开发的一个项目，在输入名称和电子邮件等详细信息后，它不会转到打印价格的代码的下一部分，然后转到下一个功能。我做错了什么？？

此外，我该怎么做才能让客户可以输入带有空格的详细信息？提前致谢。

    #include<stdio.h>
    #include<string.h>
    #include<stdlib.h>
    int option,card_num,csc,phone_number;
    char name,address,e_mail,registration;
    void membership();
    void payment();
    int main()
    {

    membership();

    return 0;

    }
    void membership()
    {
    printf("\tTHE CRUMP'S MEMBERSHIP");
    printf("\n\n This membership ...");
    printf("\n\n REGISTRATION [CONTRACTOR(A)/CORPORATION(B)]=");
    scanf("%c",&registration);
    switch (registration)
    {
    case 'A':
     printf("\n\nEnter details without any spacing.");
     printf("\nNAME:");
     scanf("%s",&name);
     printf("\nADDRESS:");
     scanf("%s",&address);
     printf("\nPHONE NUMBER:");
     scanf("%d",&phone_number);
     printf("\nE-MAIL:");
     scanf("%s",&e_mail);
     break;

    case 'B':
     printf("Enter details without any spacing.");
     printf("\nNAME OF CORPORATION:");
     scanf("%s",&name);
     printf("\nADDRESS OF CORPORATION:");
     scanf("%s",&address);
     printf("\nPHONE NUMBER OF CORPORATION:");
     scanf("%d",&phone_number);
     printf("\nE-MAIL OF CORPORATION:");
     scanf("%s",&e_mail);
     break;
     }

     if (registration=='A')
     printf("\n THE REGISTRATION FEE = |RM 50/MONTH |\t| RM 500/YEAR|");
     else if (registration=='B')
     printf("\n THE REGISTRATION FEE = |RM 200/MONTH |\t| RM 2200/YEAR|");
     }
     void payment()
     {
     printf("\n\nChoose method of payment: ");
     printf("\n\t 1- Money Transfer \n\t 2-Debit Card\n");
     scanf("%d",&option);

     if (option==1)
     {
     printf("\nYou have chosen Money Transfer.");
     printf("\nYou can transfer your money at our bank account --> 4365 4200 1471");
     printf ("\n your membership will be confirmed when we have received the payment");
     printf("\n************************************************************");
     if (registration=='A')
     {
     printf("\nNAME:%s",name);
     printf("\nADDRESS:%s",address);
     printf("\nPHONE NUMBER:%d",phone_number);
     printf("\nE-MAIL:%s",e_mail);
     }
     else if (registration=='B')
     {
     printf("\nNAME OF CORPORATION:%s",name);
     printf("\nADDRESS OF CORPORATION:%s",address);
     printf("\nPHONE NUMBER OF CORPORATION:%d",phone_number);
     printf("\nE-MAIL OF CORPORATION:%s",e_mail);
     }

     printf("\n\n your transaction completed...\n\n Enjoy your membership discount.");
     }
     else if (option==2)
     {
     printf("\nYou have chosen Credit/Debit card.");
     printf("\n Please enter your Credit/Debit card number:");
     scanf("%d",&card_num);
     printf("\n Please enter CSC code:");
     scanf("%d",&csc);
     printf("\nYour  membership will be confirmed when we have received the payment");
     printf("\n*********************************************************\n\n");

     if (registration=='A')
     {
     printf("\nNAME:%s",name);
     printf("\nADDRESS:%s",address);
     printf("\nPHONE NUMBER:%d",phone_number);
     printf("\nE-MAIL:%s",e_mail);
     }
     else if (registration=='B')
     {
     printf("\nNAME OF CORPORATION:%s",name);
     printf("\nADDRESS OF CORPORATION:%s",address);
     printf("\nPHONE NUMBER OF CORPORATION:%d",phone_number);
     printf("\nE-MAIL OF CORPORATION:%s",e_mail);
     }

     printf("\n\n Your transaction is completed...\n\n Enjoy your membership discount.");
     }

     }

Answer 1

您正在尝试将字符串读入 char 变量:

char name,address,e_mail,registration;
//...
scanf("%s",&name);

char 只能保存一个字符，而不是一个字符串。如果要读取字符串，请使用字符数组:

char name[100];
//...

并将其传递给 scanf，如下所示:

scanf("%s",name);

因为数组已经衰减为指针，因此不需要获取地址。

请注意，这需要您设置名称长度限制。例如，我选择 100-1 = 99 个字符作为限制。如果输入较长，则会发生未定义的行为，这就是您现在遇到的情况。

另请注意，您从未调用 payment ，因此这永远不会被执行。如果您希望它在membership之后执行，那么您需要调用它:

int main()
{

membership();
payment();

return 0;

}