C While循环编译但不工作问题

Question

我仍在掌握 C 循环的窍门。我不明白为什么我的 while 循环不起作用。

我在这个程序中没有收到任何错误，但发生的情况是 while 循环正在执行 else if 语句，并且不会返回到 >if 语句。但如果您在第一次猜测时输入了正确的数字，它就会执行 if。当您在第一次猜测后的任何时间尝试猜测时，它不会运行完整的 while 循环并继续显示数字“太低”。我究竟做错了什么？我该如何解决它？

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int ranNumGen();
void Right(int num);  // prompt that you guessed right
void wrong(int guess, int num);  // if else's to tell you to high to low...
void sorry(int num); // prompt for not guessing it right


int main(void)
{
    // Local declarations 
    int num;
    int guess;
    int a;

    // Sets variables  
    num = ranNumGen();
    a = 0;


    // Prompt
    printf("\nLets play a game");
    printf("\nCan you guess the number I am thinking of?");
    printf("\nI will give you a hint its a number between (1 and 20)");
    printf("\nI am also going to going to give you five tries.");
    printf("\nHave a guess! ");
    printf("Shows number to win %d", num); // shows number to win to check if it works
    scanf_s("%d", &guess);




    while (a < 4)
    {
        (a++);

        if (guess == num)
        {
            Right(num);
            break;
        }
        else if (guess < num || guess > num)
        {
            wrong(guess, num);
        }
    }


    // End promts
    if (guess == num)
    {
        printf("\nGoodbye\n");
    }
    else
    {
        sorry(num);
    }
    return 0;
}

int ranNumGen()
{
    int range;
    srand(time(NULL));
    range = 20;
    range = (rand() % range + 10) + 1;
    return range;
}

void Right(int num)
{
    printf("\n\t*******************************************");
    printf("\n\t* Wow you guessed it! Yep its %d alright. *", num);
    printf("\n\t*    You won't get it next time! :)       *");
    printf("\n\t*******************************************");
}

void wrong(int guess, int num)
{
    if (guess > num)
    {
        printf("\nYour guess is to high.", guess);
        printf("\nTry again: ");
        scanf_s("%d", &guess);
    }
    else if (guess < num)
    {
        printf("\nYour guess is to low.", guess);
        printf("\nTry again: ");
        scanf_s("%d", &guess);
    }
}

void sorry(int num)
{
    printf("\nSorry buddy, you didn't guess it...");
    printf("\nThe number was %d better luck next time.\n", num);
    return;
}

Answer 1

更改错误以使用指针参数进行猜测为

void wrong(int *guess, int num)
{
    if ((*guess) > num)
    {
        printf("\nYour guess is to high.", *guess);
        printf("\nTry again: ");
        scanf_s("%d", guess);
    }
    else if ((*guess) < num)
    {
        printf("\nYour guess is to low.", *guess);
        printf("\nTry again: ");
        scanf_s("%d", guess);
    }
}

这允许您的外部猜测变量值被错误更改