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C 函数作业构建传递数组时出现错误 需要帮助 初学者问题

转载 作者:行者123 更新时间:2023-11-30 15:36:53 26 4
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我一直在网上搜索试图解决我的构建错误。我非常确定一旦修复了这些问题,我的程序就能正常运行,但由于我还无法编译我的代码,因此很难测试。

如有任何建议,我们将不胜感激,是的,这是作业。我是 C 语言的新手,我知道我可能会犯一些愚蠢的错误。我会将所有回复视为学习机会。代码如下。错误发布后。

    // Program will take user input for student names and provide functions in
// order to sort by first name, by last name
// by score and a menu function.

#include <stdio.h>
#include <string.h>

// Prototypes for functions
int menu();
void searchLast(char [][21], char [][21],float [], int);
void searchFirst(char [][21], char [][21],float [], int);
void sortLast(char [][21], char [][21],float [], int);
void sortScore(char [][21], char [][21],float [], int);
void printRecords(char [][21], char [][21],float [], int);

int main()
{
int j,NumOfRecords, k = 0;
char FirstN[15][21],LastN[15][21];
float Score[15];
int select = 0;

// Asking for the number of records the students to add
printf("How many records would you like to enter, minimum of 5, max of 15? "); G
scanf("%d",&NumOfRecords);
for( k = 0; k < NumOfRecords; k++) // Loop to take user input and save in appropriate
// array location
{
for(j=0;j<21;j++)
{
scanf("First name: %s", &FirstN[k][j]);
scanf(" Last Name: %s", &LastN[k][j]);
scanf(" Score: %f", &Score[k]);
printf("\n");
}
}


select = menu(); // Calling menu function to assign selection to call the next function
printf("%d",select); // checking to see that selection was passed to 'select'
while (select != 0) // Sentinel loop to provide user with options to modify array output
{
if (select == 1) // prints all records
{
printRecords(FirstN,LastN,Score,NumOfRecords);
}
if (select == 2) //Searches for First name and prints associated records
{
searchFirst(FirstN,LastN,Score,NumOfRecords);
}
if (select == 3) // Searches for last name and prints associated records
{
searchLast(FirstN,LastN,Score,NumOfRecords);
}
if (select == 4) // Sorts records by score and prints associated records
{
sortScore(FirstN,LastN,Score,NumOfRecords);
}
if (select == 5) // Sorts by last name and prints associated records
{
sortLast(FirstN,LastN,Score,NumOfRecords);
}
if (select == 0) // Exits program
break;

select = menu();
}

return 0;

}

int menu() // The menu function
{
int num;
printf("Menu Options \n \n");
printf("Print Records (press 1) \n");
printf("Search by first name (press 2) \n");
printf("Search by last name (press 3) \n");
printf("Sort by score (press 4) \n");
printf("Sort by last name (press 5) \n");
printf("Exit the program (press 0) \n");
printf("Please enter option number: ");
scanf("%d", num); // Takes the selection to be passed out of the function
return num; // Returns the selection to main
}
void searchLast(char FirstName[][21],char LastName[][21], float Scores[],int NumOfRecords)
{
int j;
char Lname[1][21];
printf("Please enter last name to search for");
for (j=0;j<20;j++)
{
scanf("%s",Lname[0][j]);
}
for(j=0;j<NumOfRecords;j++)
{
if(Lname[0] == LastName[j])
{
printf("%s %s %f",FirstName[j],LastName[j],Scores[j]);
}
}

}


void searchFirst(char FirstName[][21],char LastName[][21], float Scores[],int NumOfRecords)

{
int j;
char Fname[1][21];
printf("Please enter last name to search for");
for (j=0;j<20;j++)
{
scanf("%s",Fname[0][j]);
}
for(j=0;j<NumOfRecords;j++)
{
if(Fname[0] == FirstName[j])
{
printf("%s %s %f",FirstName[j],LastName[j],Scores[j]);
}
}
}
void sortLast(char FirstName[][21],char LastName[][21], float Scores[],int NumOfRecords)
{
int j,x = 0;
int k;
for(j = 0; LastName[j] < LastName[j+1] ; j++)
{
for(k = (j+1) ; k < NumOfRecords; k++)
if (LastName[j] < LastName[k])
{
float temp = 0; // function attempts to sort Arrays saving string
char tempFirst; // values in a veriable to then be reassigned to
char tempLast; // appropriate Array index.
temp = Scores[j];
Scores[j] = Scores[k];
Scores[k] = temp;
tempLast = LastName[j];
LastName[j] = LastName[k];
LastName[k] = tempLast;
tempFirst = FirstName[j]
FirstName[j] = FirstName[k];
FirstName[k] = tempFirst;
}
void sortScore(char FirstName[15][21],char LastName[15][21], float Scores[],int NumOfRecords)

{

int j,x = 0;
int k;
for(j = 0; Scores[j] < Scores[j+1] ; j++)
{
for(k = (j+1) ; k < NumOfRecords; k++)
if (Scores[j] < Scores[k])
{
float temp = 0;
char tempFirst;
char tempLast;
temp = Scores[j];
Scores[j] = Scores[k];
Scores[k] = temp;
tempLast = LastName[j];
LastName[j] = LastName[k];
LastName[k] = tempLast;
tempFirst = FirstName[j]
FirstName[j] = FirstName[k];
FirstName[k] = tempFirst;
}


}
printRecords(FirstName,LastName,Scores,NumOfRecords);
}
void printRecords(char FirstName[][21],char LastName[][21], float Scores[],int NumOfRecords)
{
int j = 0;
for (j = 0; j < NumOfRecords ; j++)
{
printf("%s %s %f \n",FirstName[j],LastName[j],Scores[j]);

}
}

//错误:

1>c:\[....]\meg4545.c(139): warning C4047: '=' : 'char' differs in levels of indirection from 'char *'
1>c:\[....]\meg4545.c(140): error C2106: '=' : left operand must be l-value
1>c:\[....]\meg4545.c(141): warning C4047: '=' : 'char [21]' differs in levels of indirection from 'char'
1>c:\[....]\meg4545.c(141): error C2106: '=' : left operand must be l-value
1>c:\[....]\meg4545.c(143): warning C4047: '=' : 'char' differs in levels of indirection from 'char *'
1>c:\[....]\meg4545.c(143): error C2146: syntax error : missing ';' before identifier 'FirstName'
1>c:\[....]\meg4545.c(143): error C2106: '=' : left operand must be l-value
1>c:\[....]\meg4545.c(144): warning C4047: '=' : 'char [21]' differs in levels of indirection from 'char'
1>c:\[....]\meg4545.c(144): error C2106: '=' : left operand must be l-value
1>c:\[....]\meg4545.c(146): error C2143: syntax error : missing ';' before 'type'
1>c:\[....]\meg4545.c(150): error C2143: syntax error : missing ';' before 'type'
1>c:\[....]\meg4545.c(162): warning C4047: '=' : 'char' differs in levels of indirection from 'char *'
1>c:\[....]\meg4545.c(163): error C2106: '=' : left operand must be l-value
1>c:\[....]\meg4545.c(164): warning C4047: '=' : 'char [21]' differs in levels of indirection from 'char'
1>c:\[....]\meg4545.c(164): error C2106: '=' : left operand must be l-value
1>c:\[....]\meg4545.c(166): warning C4047: '=' : 'char' differs in levels of indirection from 'char *'
1>c:\[....]\meg4545.c(166): error C2146: syntax error : missing ';' before identifier 'FirstName'
1>c:\[....]\meg4545.c(166): error C2106: '=' : left operand must be l-value
1>c:\[....]\meg4545.c(167): warning C4047: '=' : 'char [21]' differs in levels of indirection from 'char'
1>c:\[....]\meg4545.c(167): error C2106: '=' : left operand must be l-value
1>c:\[....]\meg4545.c(174): error C2143: syntax error : missing ';' before 'type'
1>
1>Build FAILED.
1>

1>Time Elapsed 00:00:02.31

========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

最佳答案

可能有很多问题中的一个:

这里有一个 char 数组 (LastName[][21]):

void searchLast(char FirstName[][21],char LastName[][21], float Scores[],int NumOfRecords)
{
...
}

您正尝试在此处复制 char 数组:

LastName[j] = LastName[k];

这不是在 C 中复制字符串的方式。您必须执行如下操作:

strncpy(LastName[j], LastName[k], 21);

编辑

我忘了提及:在 C 中,如果 char 数组以 NULL ('\0') 终止,则它们会变成字符串。您必须将字符串传递给 strncpy 才能正常工作。

关于C 函数作业构建传递数组时出现错误 需要帮助 初学者问题,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22411690/

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