javascript当null时跳转到下一条记录代码修改

Question

我有一些代码运行良好，但我遇到了问题。

基本上，当它到达一个 NULL 记录时，它会向数组中添加一个 0...

在这种情况下，第二条记录为 NULL，所以我得到:

[10, 0, 20]

我需要它做的是，如果 thsub 为 NULL，则不向数组添加任何内容并继续处理下一条记录。

所以在这种情况下期望的结果是:

[10, 20]

完整代码如下:

var data = {
      "cars": [{
          "id": "1",
          "name": "name 1",
          "thsub": [{
            "id": "11",
            "name": "sub 1",
            "stats": {
              "items": 5,
            },
            "ions": null
          }, {
            "id": "22",
            "name": "sub 2",
            "stats": {
              "items": 5,
            },
            "translations": null
          }],
          "image": null
        },
    
        {
          "id": "2",
          "name": "name 2",
          "thsub": null, //this will break the code
          "image": null
        },
        {
          "id": "54",
          "name": "name something",
          "thsub": [{
            "id": "65",
            "name": "sub 1",
            "stats": {
              "items": 10,
            },
            "ions": null
          }, {
            "id": "22",
            "name": "sub 2",
            "stats": {
              "items": 10,
            },
            "translations": null
          }],
          "image": null
        }
      ]
    }
    
    
    
    var thCount = [];
    
    for (var l = 0, m = data.cars.length; l < m; l++) {
      thCount[l] = 0;
      if (data.cars[l].thsub) {
        for (var i = 0, j = data.cars[l].thsub.length; i < j; i++) {
          if (data.cars[l].thsub[i].stats) {
            thCount[l]+=data.cars[l].thsub[i].stats.items;
          }
        }
      }
    }
    
    console.log(thCount);

我该怎么做？

Answer 1

如果设置了 thsub，您只能推送一个值。

var data = { cars: [{ id: "1", name: "name 1", thsub: [{ id: "11", name: "sub 1", stats: { items: 5, }, ions: null }, { id: "22", name: "sub 2", stats: { items: 5, }, translations: null }], image: null }, { id: "2", name: "name 2", thsub: null, image: null }, { id: "54", name: "name something", thsub: [{ id: "65", name: "sub 1", stats: { items: 10, }, ions: null }, { id: "22", name: "sub 2", stats: { items: 10, }, translations: null }], image: null }] },
    thCount = [];

for (var l = 0, m = data.cars.length; l < m; l++) {
    if (data.cars[l].thsub) {
        thCount.push(0);
        for (var i = 0, j = data.cars[l].thsub.length; i < j; i++) {
            if (data.cars[l].thsub[i].stats) {
                thCount[thCount.length - 1] += data.cars[l].thsub[i].stats.items;
            }
        }
    }
}

console.log(thCount);