javascript - 如果数组具有匹配的字符串，则返回 Angular 自定义过滤器

Question

为了解决这个问题，我绞尽脑汁苦思冥想了一段时间。我觉得我快到了，但无法正确完成最后一 block 工作。这就是我想要做的。我正在创建一个自定义过滤器，它将循环遍历我的 json 数组以查看是否有“status”键，如果该“status”键包含“SUCCESS”字段，它将返回与该数组匹配的所有对象。如果“状态”键不存在，则不显示数组对象。我可以看到我的循环看起来是正确的，因为它正在确定哪个对象数组包含关键字，但是当我尝试打印出我的结果时，我什么也没看到。请帮忙!

这是演示。
https://jsfiddle.net/missggnyc/6r9oophu/20/

HTML

<div ng-app="mySessions">   
    <div ng-controller="sessionController">
  <table>
    <tr>
      <td>Session ID</td>
      <td>Session Name</td>

    </tr>
    <tr ng-repeat="cs in cSessions | successSessionFilter"> 
      <td>{{cs.id}}</td>
      <td>{{cs.session_name}}</td>          
    </tr>
  </table>
</div>

JS

var app = angular.module('mySessions', []);
app.controller("sessionController", ['$scope', function($scope){
        $scope.cSessions = [
    {"id":2,"session_name":"BD20","session_description":"","status":["INPROGRESS"]}, 
    {"id":3,"session_name":"CS03","session_description":"","status":["INPROGRESS", "SUCCESS"]},
    {"id":4,"session_name":"MIS99","session_description":"","status":["FAIL","NOTINPROGRESS"]},
     {"id":5,"session_name":"XGY7","session_description":"","status":["SUCCESS", "NOTINPROGRESS"]},
      {"id":6,"session_name":"DCCC2","session_description":""},
        {"id":7,"session_name":"IUOS33","session_description":""}
    ];
}]);
app.filter('successSessionFilter', function(){
        return function(cObj){          
            angular.forEach(cObj, function(value, key){
                angular.forEach(value, function(v, k){
                    //console.log('k is ' + k + ' and v is '+ v);
                    if(k === 'status'){
                        if(v.indexOf("SUCCESS") > -1){ //if it exists
                            //console.log("SUCCESS exists  "+ v.indexOf("SUCCESS"));
                            //console.log(v);
                            return true;
                        }
                        else { //it the status field isn't there, then don't show the object
                            return false;
                        }                       
                    }
                    else 
                        return false;
                })          
            })
    // console.log(cObj);
        }
    });

Answer 1

开始了

app.filter('successSessionFilter', function(){
  return function(items){           
    var filtered = items.filter(function(item){
      if(item['status'] && item['status'].indexOf('SUCCESS') != -1){
        return item;
      }
    })
    return filtered;
  }
});

演示 https://jsfiddle.net/ogycjbkL/