c - 对 txt 文件使用 fscanf 并忽略除字母以外的所有内容

Question

您好，我正在编写一个程序，需要从文本文件中读取并且只接受整个文件的字母。它可能是这样的

你好，我的名字叫什么。我正在考虑尝试编写一个程序:“name!”

我需要做的只是阅读字母，所以我的输出将是:

你好，我的名字就是我想写的程序名称

我有这样的东西:

while (fscanf(ifp2, "%c", &file[i]) != EOF) //scans until end of file
    {
        for (i = 0; i < 10000; i++) //loops a possible 10000, file could possibly be that big
        {
            //printf("Got inside while loop [%d]\n", i); //this just lets me see the loop
            if (fscanf(ifp2, "%c ", &file[i]) == 0) //im trying to see how i can ignore some data
            {
                fscanf(ifp2, "%c ", &file[i]); //scans in the character
            }

        }
    }

for (i = 0; i < 10000; i++)//prints the array of characters. 
{
    if(file[i] == NULL)//keeps from printing uninitialized parts of array
    {
        break;
    }
    else
    {
        if (counter % 80 == 0) //makes it print 80 characters per line
        {
            printf("\n");
        }
        printf("%c", file[i]);//prints the character
        counter++;
    }

}

我知道我可以以某种方式使用 fscanf 并且我知道它应该比这简单得多。我只需要一个*指向正确方向的指针(双关语)!

Answer 1

#include <stdio.h>
#include <stdlib.h>

int main()
{
  FILE *fp;
  char c;
  fp = fopen("sample.txt", "r");
  if (fp == NULL) {
         printf("Couldn't open file  for reading.\n");
         exit(0);
      }
  while (fscanf(fp, "%c",&c) != EOF)
    {
      if (isalpha(c))
    printf("%c", c);
    }
  printf("\n");
  return 0;
}