gpt4 book ai didi

c - 在 C 语言中扩展 Ruby - 将参数转换为 C 类型

转载 作者:行者123 更新时间:2023-11-30 15:26:59 25 4
gpt4 key购买 nike

我如何为 ruby​​ 做类似的事情。我无法找到将变量转换为对象的示例/文档。例如

Local<Object> obj = args[0]->ToObject();
Local<Array> props = obj->GetPropertyNames();

我正在用 ruby​​ 重写 Node 扩展。任何形式的帮助都会非常有帮助。谢谢

static Handle<Value> SendEmail(const Arguments& args)
{
HandleScope scope;

list<string> values;
Local<Object> obj = args[0]->ToObject();
Local<Array> props = obj->GetPropertyNames();

// Iterate through args[0], adding each element to our list
for(unsigned int i = 0; i < props->Length(); i++) {
String::AsciiValue val(obj->Get(i)->ToString());
values.push_front(string(*val));
}

// Display the values in the list for debugging purposes
for (list<string>::iterator it = values.begin(); it != values.end(); it++) {
cout << *it << endl;
}

return scope.Close(args.This());
}

最佳答案

我不完全确定我理解你的问题,因为你将此问题标记为 C 并且你的代码示例是 C++,但无论哪种方式,如果你尝试扩展 ruby​​,你都需要将 ruby​​ 值转换为C 类型,如果您计划使用 C++ 数据结构,则从 C 类型到 C++ 对象。

使用 Ruby C Api:

#include "ruby.h"
//Define module my_module (this can be any name but it should be the name of your extension
VALUE MyModule = Qnil;
//Initialization prototype - required by ruby
void Init_MyModule();
//method prototype declarations - all methods must be prefaced by method_
VALUE method_get_some_ruby_value();

//actual method
VALUE get_some_ruby_value(VALUE self, VALUE some_value)
{
//If your value is a ruby string - the StringValue function from ruby will ensure
//that you get a string no matter what, even if the type being passed is not a string.
VALUE r_string_value = StringValue(some_value);

//Now we tell the Ruby API to give us the pointer to the ruby string
//value and we assign that to a native char * in C.
char *c_string_value = RSTRING_PTR(r_string_value);

//Now do something with the char * - for example, turn it into a C++ string
std::string str(c_string_value);
// ...do something useful here...

return Qnil; // If you want to return something back to ruby, you can return a VALUE.
}
//Ruby calls this to initialize your module in ruby
VALUE Init_MyModule()
{
//This defines your module in ruby
MyModule = rb_define_module("MyModule");
//This defines the method - the module it is in, the ruby method name, the actual method ruby will call, and the number of arguments this function is expected to take
rb_define_method(MyModule, "get_some_ruby_value", get_some_ruby_value, 1);
}

如果您想了解如何在 Ruby/C/C++ 之间来回传递结构,则在开始尝试使用 C++ 对象之前,您需要彻底了解 Ruby 和 Ruby C API。

这里有一些可以帮助您入门的优秀资源:

http://silverhammermba.github.io/emberb/c/ http://java.ociweb.com/mark/NFJS/RubyCExtensions.pdf

关于c - 在 C 语言中扩展 Ruby - 将参数转换为 C 类型,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27234317/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com