C语言编程: the app wont stop after typing x

Question

我制作了这个程序，它按照我想要的方式工作，但是当我输入 x 时它应该停止，但它没有谁能告诉我为什么吗？是否有任何快捷方式或更小的方法来输入此代码？提前致谢。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
    int meat[6];
    int i;
    int total =0;
    int avg;
    char what[20];
    char end;
    int days = 0;
    char food[20];
    char drink[20];
    printf("what thing do u want to calculate the average of?(food/drink)\n");
    scanf(" %s", &what);
    if(strcmp(what, "food")==0)
    {
        printf("what sort of food did u ate ?\n");
        scanf(" %s", food);
    }
    if(strcmp(what, "drink")==0)
    {
        printf("what sort of drink did u drank ?\n");
        scanf(" %s", drink);
    }
    for(i=0; i<6; i++)        
    {
        days++;
        if(strcmp(what, "food")==0) 
        {
            printf("how many %s did u ate in day %d\n", food, i+1);
        }
        else if(strcmp(what, "drink")==0)
        {
            printf("how many liters of %s did u drank in day %d\n", drink, i+1);
        }
        scanf(" %d", &meat[i]);
        total += meat[i];
        printf("if u want to continue type y\n");

        printf("type x if u want to finish\n");
        scanf(" %c", &end);
        if((end = 'y')&&(i<5))
        {
            continue;
        }
        else if(end = 'x' && strcmp(what, "drink")==0)
        {
            avg = total / days;
            printf("\nyour average amount of liters of %s you had %d\t the total is %d\n", drink, avg, total);
        }
        else if(end = 'x' && strcmp(what, "food")==0)
        {
            avg = total / days;
            printf("\nyour average amount of %s you had %d\t the total is %d\n", food, avg, total);
        }
        break;
    }
    if(strcmp(what, food)==0)
    {        
        printf("\nyour average amount of %s you had is %d\t the total is %d\n", food, avg, total);
    }
    else if(strcmp(what, drink)==0)
    {        
        printf("\nyour average amount of liters of %s you had is %d\t the total is %d\n", drink, avg, total);
    }

    return 0;
}

Answer 1

else if(end = 'x' ...

应该是:

else if(end == 'x' ...

您可以使用 == 来测试 if 语句中的相等性。您在代码中的几个位置出现了这种情况，这是无意中执行的分配，而不是您想要通过比较用户输入是否等于特定字符来实现的目标。

将此处的 = 替换为 ==:

else if(end = 'x' && strcmp(what, "drink")==0)

这里:

else if(end = 'x' && strcmp(what, "food")==0)

这里:

if((end = 'y')&&(i<5))