javascript - 使用 .includes() 时 Switch 语句不起作用

Question

client.on('chat', function(channel, userstate, message, self){



  switch(message){
    case message.includes(emotes[0]):
      numberOfEmotes[0]++;
      console.log("Emote0 has been used " + numberOfEmotes[0] + " time(s)");
      break;
    case message.includes(emotes[1]):
      numberOfEmotes[1]++;
      console.log("Emote1 has been used " + numberOfEmotes[1] + " time(s)");
      break;
    case message.includes(emotes[2]):
      numberOfEmotes[2]++;
      console.log("Emote2 has been used " + numberOfEmotes[2] + " time(s)");
      break;
    case message.includes(emotes[3]):
      numberOfEmotes[3]++;
      console.log("Emote3 has been used " + numberOfEmotes[3] + " time(s)");
      break;
  }

/*  if(message.includes(emotes[0])){
    numberOfEmotes[0]++;
    console.log("Emote0 has been used " + numberOfEmotes[0] + " time(s)");
  }*/


  //console.log("** " + message + " **");
});

当函数 chat.on 被调用时，带有字符串的消息变量应该通过 switch 语句运行，我有一个包含不同字符串的数组，如果消息包含来自该数组的字符串，则运行该案例。但是什么也没发生，一切似乎都是对的，哪里出了问题？

Answer 1

解决此问题的一种方法是使用 switch(true) 而不是 switch(method)。这将起作用，因为它将 true(boolean) 与 case 语句进行比较。包含 emote[0] 的 Case 语句将返回 true，因此它将继续执行该 block 。希望对您有所帮助。