c# - ReIndex Number List 但按顺序保留重复项 C#

Question

我正在尝试重新排序实质上消除重复项的列表。我已经能够做到。让我感到困惑的部分是，如果有重复项，我想保留它们并保持顺序

例子-

输入 = 1,3,3,4输出 = 1,2,2,3

输入 = 1,3,5,6,6输出 = 1,2,3,4,4

如有任何帮助，我们将不胜感激。

编辑 -

我尝试过的代码。

for (int i = 1; i <= numList.Count; i++)
{
    if (numList[i - 1] == numList[i])
    {
        foreach (var item in numList.Where(x => x == numList[i - 1]))
        {
            testList.Add(item);
            i++;
        }
        foreach (var item in testList)
        {
            numList.Add(item);
        }

    }
    else
    {
        numList[i - 1] = i;
    }
}

Answer 1

你的问题与排序无关......但我想我明白你在找什么，下面的代码应该提供它:

List<Int32> numbers = new List<Int32> { 1, 3, 3, 4 };
List<Int32> result = new List<Int32>(numbers.Count);

Int32 currentValue = 1;
Int32 lastNumber = numbers[0];

for (Int32 i = 0; i < numbers.Count; ++i)
{
    Int32 number = numbers[i];

    if (numbers[i] != lastNumber)
        ++currentValue;

    result.Add(currentValue);
    lastNumber = number;
}

foreach (Int32 number in result) 
    Console.WriteLine(number); // Output: 1, 2, 2, 3

请访问this link尝试一个工作演示，它实现了以下功能:

private static List<Int32> IndexNumbers(List<Int32> input)
{
    List<Int32> numbers = input.OrderBy(x => x).ToList();
    List<Int32> result = new List<Int32>(input.Count);

    Int32 currentValue = 1;
    Int32 lastNumber = numbers[0];

    for (Int32 i = 0; i < numbers.Count; ++i)
    {
        Int32 number = numbers[i];

        if (numbers[i] != lastNumber)
            ++currentValue;

        result.Add(currentValue);
        lastNumber = number;
    }

    return result;
}