C - 初始化结构中的指针

Question

我正在 Arduino 上使用 C 语言工作。我正在尝试初始化结构(链接列表)内的指针。它是一个数据对象，所以我想立即初始化整个对象，而不是稍后在代码中使用 malloc。

const int PINS_LEN = 20;

struct Command {
  float toBrightness; //Percent
  float overTime; //Seconds
};
struct CommandNode {
  struct Command command;
  struct CommandNode *next;
};
struct Sequence {
  struct CommandNode commands;
  float startTime;
  float staggerTime;
  int pins[PINS_LEN];
};
struct SequenceNode { //Pattern
  struct Sequence sequence;
  struct SequenceNode *next;
};

struct SequenceNode pattern = {
  .sequence = {
    .commands = {
      .command = {
        .toBrightness = 100,
        .overTime = 1.0
      },
      //-=-=-=THIS IS WHERE IT DIES=-=-=-
      .next = {
        .command = {
          .toBrightness = 50,
          .overTime = 0.5
        },
        .next = NULL
      },
      //-=-=-=-=-=-=-=-=-=-=
    },
    .startTime = 0.0,
    .staggerTime = 1.0,
    .pins = {0, 1, 2, 3, 4, 5}
  },
  .next = NULL
};

Answer 1

正如评论中所说 - 您需要指针但提供结构的主要问题，解决此问题的一种变体可能是:

struct CommandNode next = {.command = {.toBrightness = 50, .overTime = 0.5}, .next = NULL};
struct SequenceNode pattern = {.sequence = {
        .commands = {
                .command = {.toBrightness = 100, .overTime = 1.0},
                .next = &next},
        .startTime = 0.0,
        .staggerTime = 1.0,
        .pins = {0, 1, 2, 3, 4, 5}
    },
    .next = NULL};