通过在函数中传递字符串来创建获胜条件

Question

每当我编译代码时，无论传递什么整数，它都会打印所有可能的场景。有关如何解决此问题以及为什么会发生这种情况的任何帮助吗？

#include <stdio.h>
void *get_plays(char *player1, char *player2)
{
    printf ("Player 1 chooses to play:   ");
    scanf("%s", player1);
    printf ("Player 2 chooses to play:   ");
    scanf("%s", player2);
    return player1;
    return player2;
}
int *check_for_winner(char *player1, char *player2, int condition)
{

    if (player1==player2){
        condition = 0;
    }
    else if(player1=="rock" && player2 == "scissors"){
        condition = 1;
    }
    else if(player1=="paper" && player2 == "scissors"){
        condition = 2;
    }
    else if(player1=="rock" && player2 == "paper"){
        condition = 2;
    }
    else if(player1=="paper" && player2 == "rock"){
        condition = 1;
    }
    else if(player1=="scissors" && player2 == "papper"){
        condition = 1;
    }
    else (player1=="scissors" && player2 == "rock");{
        condition = 1;
    }
}
void *print_plays(char *player1, char *player2)
{
    printf("Player 1 has played %s \n",player1);
    printf("Player 2 has played %s \n",player2);
}
void *print_winner(int condition)
{
    if (condition = 0){
        printf("It's a tie\n");
    }
    else if (condition = 1){
        printf("Player 1 wins\n");
    }
    else (condition = 2);{
        printf("Player 2 wins\n");
    }
}
int main(void)
{
    char player1[10];
    char player2[10];
    int win;
    get_plays(player1, player2);
    check_for_winner(player1, player2, win);
    print_plays(player1, player2);
    print_winner(win);      
    return;
}

当我编译时，它会打印“玩家 1 获胜”和“玩家 2 获胜”，不知道为什么或如何修复它，甚至不知道为什么会发生。我对 C 还很陌生，所以任何帮助将不胜感激。谢谢。

Answer 1

#include <stdio.h>
#include <string.h>

void
get_plays (char *choice1, char *choice2)
{
    printf ("Choices: 'paper' - 'rock' - 'scissors'\n");
    printf ("Player 1 chooses to play: ");
    scanf ("%s", choice1);

    printf ("Player 2 chooses to play: ");
    scanf ("%s", choice2);
}

int
check_for_winner (const char *choice1, const char *choice2)
{
    // paper wins rock but scissors does not and equals itself
    if (strcmp (choice1, "paper") == 0)
    {
        if (strcmp (choice2, "rock") == 0)
            return 1;

        if (strcmp (choice2, "scissors") == 0)
            return 2;

        return 0;
    }

    // rock wins scissors but paper does not and equals itself
    if (strcmp (choice1, "rock") == 0)
    {
        if (strcmp (choice2, "scissors") == 0)
            return 1;

        if (strcmp (choice2, "paper") == 0)
            return 2;

        return 0;
    }

    // scissors wins paper but rock does not and equals itself
    if (strcmp (choice1, "scissors") == 0)
    {
        if (strcmp (choice2, "paper") == 0)
            return 1;

        if (strcmp (choice2, "rock") == 0)
            return 2;

        return 0;
    }

    return 0;
}

int main ()
{
    char choice1 [10];
    char choice2 [10];
    int winner;
    char q;

    char *result[3] = {
        "No one is the winner", 
        "Player 1 is the winner!!!", 
        "Player 2 is the winner!!!"
    };

    printf ("Choose 'q' to exit\n");
    printf ("------------------------------------------------------------\n");
    while (q != 'q')
    {
        get_plays (&choice1[0], &choice2[0]);
        winner = check_for_winner (choice1, choice2);

        printf ("------------------------------------------------------------\n");
        printf ("The result: %s\n",  result[winner]);
        printf ("------------------------------------------------------------\n");
        getc (stdin);
        scanf ("%c", &q);
    }
    return 0;
}

希望代码对您有所帮助!