c# - 将不同的 Bundle Virtual Path 联合成一个

Question

我在 BundleConfig.config 上定义了多个 Bundle 虚拟路径，其中每个虚拟路径都关联了多个 javascript 路径文件。

我想要的是将所有这些虚拟路径合并为一个。

例如，我有以下代码:

bundles.Add(new ScriptBundle(BundlesVirtualPaths.EditorV2.Main).Include(
                                "~/Scripts/EditorV2/main.js"
                    ));

bundles.Add(new ScriptBundle(BundlesVirtualPaths.EditorV2.Main2).Include(
                                "~/Scripts/EditorV2/main2.js"
                    ));

bundles.Add(new ScriptBundle(BundlesVirtualPaths.EditorV2.Main3).Include(
                                "~/Scripts/EditorV2/main3.js"
                    ));

我想要的是远离做这样的事情:

bundles.Add(new ScriptBundle(BundlesVirtualPaths.EditorV2.AllScripts).Include(
                            BundlesVirtualPaths.EditorV2.Main,
                            BundlesVirtualPaths.EditorV2.Main2,
                            BundlesVirtualPaths.EditorV2.Main3
                ));

这样可以吗？我可以吗？

Answer 1

你可以尝试这样的事情:

public static class BundleHelpers
{
    public static BundleCollection JoinScriptBundle(this BundleCollection bundleCollection, string virtualPath, params string[] bundlesToJoin)
    {
        var bundleResolver = new BundleResolver(bundleCollection);
        Bundle allScriptBundle = new ScriptBundle(virtualPath);
        foreach (var bundle in bundlesToJoin)
        {
            foreach (var scriptPath in bundleResolver.GetBundleContents(bundle))
            {
                allScriptBundle = allScriptBundle.Include(scriptPath);
            }
        }
        bundleCollection.Add(allScriptBundle);
        return bundleCollection;
    }
}

然后你可以加入你的包:

bundles.JoinScriptBundle("~/bundle/allscript", "~/bundles/jquery", "~/bundles/jqueryval", "~/bundles/modernizr");