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c - 输入 switch case 将每个变量重置为零和一些提示

转载 作者:行者123 更新时间:2023-11-30 14:47:28 24 4
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我在考试中编写了这段代码,但它有一些问题(因此我失败了)。

在通过我的主板进行调试时(我有一个 atmel atmega328p Xplained mini),我不知道为什么,但是在进入主开关以及开关(当前状态)之间时>检查案例:我所有的状态变量都重置为零。如果我通过模拟器调试它,它似乎工作正常。

如果我将代码上传到开发板,它的工作效果就会很差,就像它无法识别某些中断一样。

另外我还想问你一件事。我在考试中使用了一个子板,它可以防止访问 PWM 输出的正确引脚,而且我必须驱动特定的输出(我的子板的 LED,例如在这段代码中我必须驱动 PORTC5 和 PORTC4),所以我必须手动实现 PWM。我尝试实现您可以在代码中看到的解决方案(我使用 1ms 的计时器)。有没有更简单、更智能的解决方案?

你能帮我吗?

#include <avr/io.h>
#include <avr/interrupt.h>

typedef enum{checkled, heatingup, exposure, stop} machine;
machine currentstate=checkled;

typedef enum{twenty, fourty, sixty, eighty} brightness;
brightness light=twenty;

typedef enum{twoseconds, fourseconds, eightseconds, sixteenseconds} exposuretime;
exposuretime time=twoseconds;

volatile uint16_t tick=0;
volatile uint16_t oldtick=0;

volatile uint8_t flagchanged=0;

ISR(PCINT2_vect)
{
if((PIND&(1<<PIND2))==0)
{
if(currentstate==checkled)
currentstate=heatingup;
}

if((PIND&(1<<PIND3))==0)
{
if(currentstate==exposure || currentstate==heatingup)
{
currentstate=stop;
PORTC&=~(1<<PORTC4);
tick=0;
}
}

if((PIND&(1<<PIND4))==0)
{
if(currentstate==checkled)
{
flagchanged=1;

if(time==sixteenseconds)//rise time
;
else if(time==eightseconds)
time=sixteenseconds;
else if(time==fourseconds)
time=eightseconds;
else if(time==twoseconds)
time=fourseconds;
}
}

if((PIND&(1<<PIND5))==0)
{
if(currentstate==checkled)
{
flagchanged=1;

if(time==sixteenseconds)//decrease time
time=eightseconds;
else if(time==eightseconds)
time=fourseconds;
else if(time==fourseconds)
time=twoseconds;
else if(time==twoseconds)
;
}
}

if((PIND&(1<<PIND6))==0)
{
if(currentstate==checkled)
{
flagchanged=1;

if(light==eighty)//rise brightness
;
else if(light==sixty)
light=eighty;
else if(light==fourty)
light=sixty;
else if(light==twenty)
light=fourty;
}
}

if((PIND&(1<<PIND7))==0)
{
if(currentstate==checkled)
{
flagchanged=1;

if(light==eighty)//decrease brightness
light=sixty;
else if(light==sixty)
light=fourty;
else if(light==fourty)
light=twenty;
else if(light==twenty)
;
}
}

}

ISR(TIMER1_COMPA_vect)
{
tick++;
}

int main(void)
{
//DDRs
DDRD&=~((1<<PIND2)|(1<<PIND3)|(1<<PIND4)|(1<<PIND5)|(1<<PIND6)|(1<<PIND7));//input
PORTD|=(1<<PORTD2)|(1<<PORTD3)|(1<<PORTD4)|(1<<PORTD5)|(1<<PORTD6)|(1<<PORTD7);//pull-up resistors

DDRC|=(1<<PORTC0)|(1<<PORTC1)|(1<<PORTC2)|(1<<PORTC3)|(1<<PORTC4)|(1<<PORTC5);//output

//PCINTERRUPT
PCICR|=(1<<PCIE2);
PCMSK2|=(1<<PCINT18)|(1<<PCINT19)|(1<<PCINT20)|(1<<PCINT21)|(1<<PCINT22)|(1<<PCINT23);

//TIMER
TCCR0A|=(1<<WGM01);
TIMSK0|=(1<<OCIE0A);
OCR0A=15;//((clockfrequency/prescaler)*time)-1 - 1millisecond
TCCR0B|=(1<<CS02)|(1<<CS00);

sei();

volatile uint8_t counter=0;
volatile uint16_t check=0;

while(1)
{
switch (currentstate)//FORM HERE
{
case checkled://TO HERE every variable is reset to ZERO
if(flagchanged!=0)
{


if(light==twenty)//led intesita
{
PORTC&=~(1<<PORTC0);
PORTC&=~(1<<PORTC1);
}
else if(light==fourty)
{
PORTC|=(1<<PORTC0);
PORTC&=~(1<<PORTC1);
}
else if(light==sixty)
{
PORTC&=~(1<<PORTC0);
PORTC|=(1<<PORTC1);
}
else if(light==eighty)
{
PORTC|=(1<<PORTC0);
PORTC|=(1<<PORTC1);
}


if(time==twoseconds)//led time
{
PORTC&=~(1<<PORTC2);
PORTC&=~(1<<PORTC3);
}
else if(time==fourseconds)
{
PORTC|=(1<<PORTC2);
PORTC&=~(1<<PORTC3);
}
else if(time==eightseconds)
{
PORTC&=~(1<<PORTC2);
PORTC|=(1<<PORTC3);
}
else if(time==sixteenseconds)
{
PORTC|=(1<<PORTC2);
PORTC|=(1<<PORTC3);
}

flagchanged=0;
}
break;

case heatingup:
if(tick<=3000)
{
if(tick!=oldtick)
{
oldtick=tick;

if((tick%500)==0)//duty cycle al 50%
PORTC^=(1<<PORTC5);

if((tick%5)==0)//5% duty cycle
{

if(counter<=94)//per il 95% del periodo sta spento
{
PORTC&=~(1<<PORTC4);
}
else if(counter>=95 && counter<=101)//per il 5% del periodo sta acceso
{

if(counter==101)
{
PORTC&=~(1<<PORTC4);
counter=0;
}
else
PORTC|=(1<<PORTC4);

}

counter++;
}
}
}
else
{
currentstate=exposure;
counter=0;
tick=0;

PORTC|=(1<<PORTC5);

//checking time of how much the lamp needs to be light up
switch (time)
{
case twoseconds:
check=2000;
break;

case fourseconds:
check=4000;
break;

case eightseconds:
check=8000;
break;

case sixteenseconds:
check=16000;
break;
}
}
break;

case exposure:
if(tick<=check)
{
switch (light)//Checking duty cycle
{
case twenty://20% duty cycle
if(tick!=oldtick)
{
if((tick%20)==0)
{

if(counter<=4)//80% off
{
PORTC&=~(1<<PORTC4);
}
else if(counter>=5 && counter<=6)//20% on
{
if(counter==6)
{
PORTC&=~(1<<PORTC4);
counter=0;
}
else
PORTC|=(1<<PORTC4);

}

counter++;
}
}
break;

case fourty://40% duty cycle
if(tick!=oldtick)
{
if((tick%20)==0)
{

if(counter<=3)//60% off
{
PORTC&=~(1<<PORTC4);
}
else if(counter>=4 && counter<=6)//40% on
{
if(counter==6)
{
PORTC&=~(1<<PORTC4);
counter=0;
}
else
PORTC|=(1<<PORTC4);

}

counter++;
}
}
break;

case sixty://60% duty cycle
if(tick!=oldtick)
{
if((tick%20)==0)
{

if(counter<=2)//40% off
{
PORTC&=~(1<<PORTC4);
}
else if(counter>=3 && counter<=6)//60% on
{
if(counter==6)
{
PORTC&=~(1<<PORTC4);
counter=0;
}
else
PORTC|=(1<<PORTC4);

}

counter++;
}
}
break;

case eighty://80% duty cycle
if(tick!=oldtick)
{
if((tick%20)==0)
{

if(counter<=1)//20% off
{
PORTC&=~(1<<PORTC4);
}
else if(counter>=2 && counter<=6)//80% on
{
if(counter==6)
{
PORTC&=~(1<<PORTC4);
counter=0;
}
else
PORTC|=(1<<PORTC4);

}

counter++;
}
}
break;

}
}
else
{
PORTC&=~(1<<PORTC4);
PORTC&=~(1<<PORTC5);
currentstate=checkled;
flagchanged=1;
}

break;

case stop://Emergency stop
if(tick<=2000)
{
if(tick!=oldtick)
{
oldtick=tick;
if((tick%250)==0)
PORTC|=(1<<PORTC5);
}
}
else
{
PORTC&=~(1<<PORTC5);
flagchanged=1;
currentstate=checkled;
}
break;
}
}
}

最佳答案

在主代码中,启用了定时器0的输出比较中断

TIMSK0|=(1<<OCIE0A);

但是您没有该 vector 的中断处理程序(您有 TIMER1_COMPA_vect - 用于定时器 1)。

因此,当定时器中断发生时,它由默认 vector 处理,该 vector 只是将控制重定向到重置 vector ,这会导致应用程序从头开始,包括变量初始化,这会导致您所有意外的行为正在观察。

因此,解决方案很简单:要么禁用 OCIE0A,要么为此中断创建一个处理程序。

关于c - 输入 switch case 将每个变量重置为零和一些提示,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51221033/

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