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javascript - 迭代一个对象并平均一些值

转载 作者:行者123 更新时间:2023-11-30 14:41:11 24 4
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我有一个像这样的数据结构allDataJson:

[ { year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'POL',
coverage: 95.13 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'DIPH',
coverage: 95.14 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'TET',
coverage: 95.44 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'PER',
coverage: 95.12 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'EP B',
coverage: 94.72 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'HIB',
coverage: 94.33 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'MEASLES',
coverage: 91.06 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'MUMPS',
coverage: 91.06 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'RUB',
coverage: 91.06 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'VAR',
coverage: 1.86 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'Men C',
coverage: 89.33 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'PNC',
coverage: 91.84 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'EP A',
coverage: 0.87 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'ROTA',
coverage: 6.39 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'Men B',
coverage: 0 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'Men ACYW',
coverage: 0 },
{ year: 2016,
country: 'Italy',
region: 'Valle d\'Aosta',
vaccine: 'POL',
coverage: 90.86 },
{ year: 2016,
country: 'Italy',
region: 'Valle d\'Aosta',
vaccine: 'DIPH',
coverage: 90.77 },
{ year: 2016,
country: 'Italy',
region: 'Valle d\'Aosta',
vaccine: 'TET',
coverage: 91.32 },
{ year: 2016,
country: 'Italy',
region: 'Valle d\'Aosta',
vaccine: 'PER',
coverage: 90.77 },
{ year: 2016,
country: 'Italy',
region: 'Valle d\'Aosta',
vaccine: 'EP B',
coverage: 90.67 }, ...]

我想创建另一个类似于 allDataJsondataJson 对象,但它会对一些值​​求平均值。

例如,在 2016 年我想创建一个新的 DTP 疫苗值,它计算 DIPHTETPER.

同样在 2016 年,我想研制一种 MMRV 疫苗,其值(value)是 MEASLESMUMPSRUBVAR 值。

所以 dataJson 看起来像(它包含新值,那些未修改的值,不包含我取平均的值):

[ { year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'POL',
coverage: 95.13 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'DTP',
coverage: 95.23 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'EP B',
coverage: 94.72 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'HIB',
coverage: 94.33 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'MMRV',
coverage: 68.76 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'Men C',
coverage: 89.33 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'PNC',
coverage: 91.84 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'EP A',
coverage: 0.87 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'ROTA',
coverage: 6.39 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'Men B',
coverage: 0 },
{ year: 2016,
country: 'Italy',
region: 'Piemonte',
vaccine: 'Men ACYW',
coverage: 0 },
{ year: 2016,
country: 'Italy',
region: 'Valle d\'Aosta',
vaccine: 'POL',
coverage: 90.86 },
{ year: 2016,
country: 'Italy',
region: 'Valle d\'Aosta',
vaccine: 'DTP',
coverage: 90.95 },
{ year: 2016,
country: 'Italy',
region: 'Valle d\'Aosta',
vaccine: 'EP B',
coverage: 90.67 }, ...]

这是我的代码:

global.allDataJson = []; // all data
global.dataJson = []; // data I'm interested in

methods.elaborate = function() {
for(var i = 0; i < allDataJson.length; i++) {
var val = allDataJson[i];
switch(val.year) {
case 2016:
if(val.region == 'Piemonte') {
var diph = 0;
var tet = 0;
var per = 0;
var mea = 0;
var mum = 0;
var rub = 0;
var vari = 0;
if(val.vaccine == 'DIPH') {
diph = val.coverage;
}
else if(val.vaccine == 'TET') {
tet = val.coverage;
}
else if(val.vaccine == 'PER') {
per = val.coverage;
}
else if(val.vaccine == 'MEASLES') {
mea = val.coverage;
}
else if(val.vaccine == 'MUMPS') {
mum = val.coverage;
}
else if(val.vaccine == 'RUB') {
rub = val.coverage;
}
else if(val.vaccine == 'VAR') {
vari = val.coverage;
}
else {
var newObj = createJsonObject(2016, val.country, val.vaccine, 'Piemonte', val.coverage);
dataJson.push(newObj);
}
// create DTP value
var avgDtp = (diph + tet + per)/3;
var newObj = createJsonObject(2016, val.country, 'DTP', 'Piemonte', avgDtp);
dataJson.push(newObj);
// create MMRV value
var avgMmrv = (mea + mum + rub + vari)/4;
var newObj = createJsonObject(2016, val.country, 'MMRV', 'Piemonte', avgMmrv);
dataJson.push(newObj);
}
if(val.region == 'Lombardia') {
// same thing for another region
}
// same thing for each region

break;

case 2000:
// similar thing for each year
break;

default:
console.log('Switch err in elaborate() function');
}
}
}

有没有更聪明的方法来做到这一点?

最佳答案

您应该创建一个变量来维护您的过滤配置:

global.config = [
{
year: 2016,
vaccine: 'DTP',
country: 'Italy',
region: 'Piemonte',
combinedData: [ 'DIPH', 'TET', 'PER' ]
},
{
year: 2016,
vaccine: 'MMRV',
country: 'Italy',
region: 'Piemonte',
combinedData: [ 'MEASLES', 'MUMPS', 'RUB', 'VAR' ]
},
// and so on
]

并将其作为参数传递给函数elaborate:

methods.elaborate = function() {
for (var i=0; i<config.length; i++ ) {
var filterDataJson = allDataJson.filter(function(data) {
return data.country === data.country && data.region === config[i].region && data.year === config[i].year && config[i].combinedData.includes(data.vaccine);
})

if (filterDataJson.length > 0) {
var average = 0;
for (var j=0; j<filterDataJson.length; j++) {
average += filterDataJson[j].coverage / filterDataJson.length;
}
var newObj = createJsonObject(config[i].year, config[i].vaccine, config[i].country, config[i].region, average);
dataJson.push(newObj);
} else {
console.log("Some meaningful error message here");
}
}
}

除非你有充分的理由,否则永远不要在这么多子条件下使用 switch 和 if-else。

编辑:如果所有地区的疫苗都相同,那么您可以像这样对它们进行分组

global.config = [
{
year: 2016,
vaccine: 'DTP',
country: 'Italy',
regions: ['Piemonte', 'Lombardia', 'Sicilia', 'Sardegna', ...],
combinedData: [ 'DIPH', 'TET', 'PER' ]
},
{
year: 2016,
vaccine: 'MMRV',
country: 'Italy',
regions: ['Piemonte', 'Lombardia', 'Sicilia', 'Sardegna', ...],
combinedData: [ 'MEASLES', 'MUMPS', 'RUB', 'VAR' ]
},
// and so on
]

elaborate 函数需要稍微扭曲一下:

methods.elaborate = function() {
for (var i=0; i<config.length; i++ ) {
for (var k=0; k<config[i].regions.length; k++) {
var filterDataJson = allDataJson.filter(function(data) {
return data.country === data.country && data.region === config[i].regions[k] && data.year === config[i].year && config[i].combinedData.includes(data.vaccine);
})

if (filterDataJson.length > 0) {
var average = 0;
for (var j=0; j<filterDataJson.length; j++) {
average += filterDataJson[j].coverage / filterDataJson.length;
}
var newObj = createJsonObject(config[i].year, config[i].vaccine, config[i].country, config[i].regions[k], average);
dataJson.push(newObj);
} else {
console.log("Some meaningful error message here");
}
}
}
}

关于javascript - 迭代一个对象并平均一些值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49645185/

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