javascript - 提前 5 个工作日

Question

我需要获取从当天算起的 5 个工作日的数组。

今天是:06/04/2018

我需要的输出是:

{
     0: 06/01/2018, //fri.
     1: 05/31/2018, //thur.
     2: 05/30/2018, //wed.
     3: 05/29/2018, //tue.
     4: 05/28/2018 //mon.
};

这是我的代码和当前输出:

{
     0: business_day_from_date(1),//sun. i don't want weekends
     1: business_day_from_date(2),//sat i don't want weekends
     2: business_day_from_date(3),//fri.
     3: business_day_from_date(4),//thur.
     4: business_day_from_date(5),//wed.
}


function business_day_from_date(daysAgo){
    var date = new Date();
    date.setDate(date.getDate() - daysAgo);
    return date.getMonth() + "-" + date.getDate() + "-" + date.getFullYear();
}

工作日是:

• 星期一
• 星期二
• 星期三
• 星期四
• 星期五

Answer 1

以下应该有效:

function business_day_from_date(daysAgo, date) {//pass date in
  const result = [];
  const d = new Date(date);//do not mutate date passed in
  while (daysAgo > 0) {//while we have not enough work days
    d.setDate(d.getDate() - 1);//take one day of the copy of the date passed in
    if (d.getDay() !== 0 && d.getDay() !== 6) {//if not sat or sun
      daysAgo--;//we found one
      result.push(new Date(d));//add copy of the found one to result
    }
  }
  return result.reverse();//oldest to newest
}
function formatDate(date){
  return (date.getMonth()+1) + "-" + date.getDate() + "-" + date.getFullYear()
}
console.log(
  "date passed in:",formatDate(new Date()),
  business_day_from_date(3, new Date()).map(
    function(date){return formatDate(date);}
  )
)

使用 daysAgo 从传入的日期返回天数并获取所有工作日，但不包括传入的日期。

function business_day_from_date(daysAgo, date) {//pass date in
  const result = [];
  const d = new Date(date);//do not mutate date passed in
  const end = new Date(d);
  d.setDate(d.getDate()-daysAgo);//go back the daysAgo value
  while (d.getTime()<end.getTime()) {//while we have not passed date passed in
    if (d.getDay() !== 0 && d.getDay() !== 6) {//if not sat or sun
      daysAgo--;//we found one
      result.push(new Date(d));//add copy of the found one to result
    }
    d.setDate(d.getDate() + 1);//add a day
  }
  return result;//oldest to newest, use .reverse to get newest to oldest
}
function formatDate(date){
  return (date.getMonth()+1) + "-" + date.getDate() + "-" + date.getFullYear()
}
console.log(
  "date passed in:",formatDate(new Date()),
  business_day_from_date(3, new Date()).map(
    function(date){return formatDate(date);}
  )
)