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c# - 整数转罗马格式

转载 作者:行者123 更新时间:2023-11-30 14:30:35 25 4
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我正在尝试获取 0-50 之间的罗马数字。我只是在文本框上写下整数并按下按钮,我想在标签中使用它的罗马格式。

我已经编写了代码,它在 0-50 数字范围内运行良好。

但是,我认为我的解决方案不是最优的。

任何人都可以帮助我,我怎样才能使它更优化。

int number = Convert.ToInt32( tb_input.Text);
StringBuilder sb = new StringBuilder();
sb= IntToRoman(number, sb);



Label1.Text =sb.ToString();


public StringBuilder IntToRoman(int number, StringBuilder sb)
{
int flag = 0;
if (number >= 50 && flag==0)
{
sb.Append("L");
IntToRoman(number - 50, sb);
flag = 1;
}
if (number >= 10 && flag == 0)
{
sb.Append("X");
IntToRoman(number - 10, sb);
flag = 1;

}
if (number >= 9 && flag == 0)
{
sb.Append("IX");
IntToRoman(number - 9, sb);
flag = 1;
}

if (number >= 5 && flag == 0)
{
sb.Append("V");
IntToRoman(number - 5, sb);
flag = 1;
}
if (number >= 4 && flag == 0)
{
sb.Append("IV-");
IntToRoman(number - 4, sb);
flag = 1;
}

if (number >= 1 && flag == 0)
{
sb.Append("I");
IntToRoman(number - 1, sb);
flag = 1;
}

if (number ==0)
{
return sb;

}
return sb;
}

最佳答案

非常简单的代码,适用于任何数字...

    public static List<string> romanNumerals = new List<string>() { "M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I" };
public static List<int> numerals = new List<int>() { 1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1 };

public static string ToRomanNumeral(int number)
{
var romanNumeral = string.Empty;
while (number > 0)
{
// find biggest numeral that is less than equal to number
var index = numerals.FindIndex(x => x <= number);
// subtract it's value from your number
number -= numerals[index];
// tack it onto the end of your roman numeral
romanNumeral += romanNumerals[index];
}
return romanNumeral;
}

用法...

ToRomanNumeral(58) = 'LVIII'
ToRomanNumeral(2014) = 'MMXIV'

关于c# - 整数转罗马格式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22392810/

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