c - 语法和解析错误

Question

我在第 9 行不断收到语法错误，并在第 31、32、33 和 38 行出现解析错误...我不知道为什么。谁能帮我吗？

#include stdio.h<> <-----there are all correct in the code but don't show on here
#include stdlib.h<>
#include math.h<> 

int hamlength;
int pbit;
int hamcode;

String char  *hamming = NULL;

void enter_params(){
    printf("Enter length of the Hamming code:_\n");
      scanf("%d",&hamlength);
 printf("Enter the parity(0=even, 1=odd):_\n");
      scanf("%d",&pbit);
    hamming = (char *)malloc(hamlength * sizeof(char));
}

void free_memory(){
if (hamming != NULL)
    free (hamming);
return;
}

 1. List item

void correct_hamming(){
int errorBit=0;
int currentBit;
int i;
int j;
int k;
printf("Enter the Hamming Code:_\n");
scanf("%s", hamming);
for(i = 1, i < hamlength; i = i * 2){
for(j = i; j < hamlength; j += 2 * i){
for(k = j; k < hamlength && k < currentBit; k++){
        currentBit = currentBit ^ hamming [hamlength - k];
        if (k != i)
        currentBit = currentBit ^ hamming[hamlength - k];       
}
errorBit += ((currenttBit ^(hamming[hamlength - i] - '0')) + i);
}
}
}
int main(){
      int choice=0;
      while(choice!=3){
         printf("1) Set parameters\n");
         printf("2) Check Hamming Code\n");
         printf("3) Exit\n");        
         printf("Enter selection:_\n");
            scanf("%d",&choice);
         switch(choice){
            case 1: enter_params(); 
               break; 
            case 2:  correct_hamming();
               break;
           case 3: printf("dueces!");
                    break;


         }
      }
      return 0;
   }

Answer 1

#include stdio.h<> <-----there are all correct in the code but don't show on here
#include stdlib.h<>
#include math.h<> 

你的意思是

#include <stdio.h> 
#include <stdlib.h>
#include <math.h> 

？

String char *hamming = NULL;

什么是String在这里做什么？它不是 C 关键字。删除String从那条线。您的代码充满语法和逻辑错误。

<小时/>

 1. List item // should be commented

<小时/>

errorBit += ((currenttBit ^(hamming[hamlength - i] - '0')) + i);

这里有错字currenttBit应该是当前位

<小时/>

for(i = 1, i < hamlength; i = i * 2)

替换,与 ;

<小时/>

在 main()功能

  int choice=0;
  while(choice!=3)

用户什么时候会输入他的选择？