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javascript - jsgrid 入门示例不起作用

转载 作者:行者123 更新时间:2023-11-30 14:27:17 26 4
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对于我的一个项目,我必须使用 jsgrid ( http://js-grid.com )。

为了测试如何使用 jsgrid,我想做“入门”示例 ( http://js-grid.com/getting-started 。我的问题是,在我看来,我按照示例中的说明做了一切,但最终没有奏效。

我错过了什么?

这是我的代码:

<!DOCTYPE html>
<html>
<head>
<link type="text/css" rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.css" />
<link type="text/css" rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid-theme.min.css" />

<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.js"></script>
<script>
var clients = [
{ "Name": "Otto Clay", "Age": 25, "Country": 1, "Address": "Ap #897-1459 Quam Avenue", "Married": false },
{ "Name": "Connor Johnston", "Age": 45, "Country": 2, "Address": "Ap #370-4647 Dis Av.", "Married": true },
{ "Name": "Lacey Hess", "Age": 29, "Country": 3, "Address": "Ap #365-8835 Integer St.", "Married": false },
{ "Name": "Timothy Henson", "Age": 56, "Country": 1, "Address": "911-5143 Luctus Ave", "Married": true },
{ "Name": "Ramona Benton", "Age": 32, "Country": 3, "Address": "Ap #614-689 Vehicula Street", "Married": false }
];

var countries = [
{ Name: "", Id: 0 },
{ Name: "United States", Id: 1 },
{ Name: "Canada", Id: 2 },
{ Name: "United Kingdom", Id: 3 }
];

$("#jsGrid").jsGrid({
width: "100%",
height: "400px",

inserting: true,
editing: true,
sorting: true,
paging: true,

data: clients,

fields: [
{ name: "Name", type: "text", width: 150, validate: "required" },
{ name: "Age", type: "number", width: 50 },
{ name: "Address", type: "text", width: 200 },
{ name: "Country", type: "select", items: countries, valueField: "Id", textField: "Name" },
{ name: "Married", type: "checkbox", title: "Is Married", sorting: false },
{ type: "control" }
]
});
</script>
</head>
<body>
<div id="jsGrid"></div>
</body>
</html>

最佳答案

您的脚本代码在 DOM 准备好之前运行。我把你的脚本包在中间:

$(document).ready(function() {

和:

});

它在显示的表格中运行良好。有关一些解释,请参阅 here .

jsGrid 是一个很棒的工具。不幸的是,它的诊断几乎为零。有些事情可能是错误的,比如一个简单的错字,但根本没有迹象表明哪里出了问题。

关于javascript - jsgrid 入门示例不起作用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51730839/

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