objective-c - 如何访问 C 函数中的 N 个参数并将相同的 N 传递给下一个？

Question

例如，这是我的 C(和 Objective-C)方法，如下所示。

void ALERT(NSString *title, NSString *message,NSString *canceBtnTitle,id delegate,NSString *otherButtonTitles, ... )
{
    // HERE I CAN ACCESS ALL THOSE ARGUMENTS
    // BUT I AM NOT SURE How to access additional arguments, supplied using ... ?

UIAlertView *alertView=[[UIAlertView alloc] initWithTitle:title 
                                                  message:message 
                                                 delegate:delegate 
                                        cancelButtonTitle:canceBtnTitle 
                                        otherButtonTitles:// how to pass those params here?];
}

正如您所注意到的，我还必须在 UIAlertView 的 init 方法中传递这些参数。我不确定如何将这些参数发送到 otherButtonTitles 中。我可以通过以下方式调用这个方法。

ALERT(@"My Alert Title",@"Alert Subtitle",@"YES",viewCtr,@"No",@"May Be",@"Cancel",nil);

ALERT(@"Alert Title",@"Alert Subtitle",@"OK",viewCtr,@"Cancel",nil);

ALERT(@"Alert Title",@"Alert Subtitle",@"OK",viewCtr,nil);

ALERT(@"Alert Title",@"Alert Subtitle",@"OK",viewCtr,@"Option1",@"Option2",nil);

Answer 1

听起来您需要了解 va_arg(以及 va_list、va_start、va_end)。

Here's a tutorial on the subject .

此外，a fine Apple tech note entitled "How can I write a method that takes a variable number of arguments, like NSString's +stringWithFormat:?"

编辑添加:

听起来你想做va_copy。

啊，here is a related question .