javascript - 从现有 JSON 数组的嵌套键/值创建一个新的 JSON 数组

Question

我有一个对象数组，它们的结构总是这样的:

var initialJSON = [  
  {  
     "id":"01",
     "name":"Jane",
     "project":{  
        "title":"Alpha",
        "description":"Lorem ipsum dolor sit amet, consectetur adipiscing elit",
        "city":"New York"
     },
     "dateCreated":"2018-04-28 04:11:16 UTC"
   },
   {  
     "id":"02",
     "name":"Sarah",
     "project":{  
       "title":"Beta",
       "description":"Lorem ipsum dolor sit amet, consectetur adipiscing elit",
       "city":"London"
     },
      "dateCreated":"2018-04-28 04:11:29 UTC"
    },
    {  
      "id":"03",
      "name":"Mia",
      "project":{  
         "title":"Gamma",
         "description":"Lorem ipsum dolor sit amet, consectetur adipiscing elit",
         "city":"Paris"
      },
      "dateCreated":"2018-04-28 04:11:29 UTC"
   }
];

我的目标是创建一个新的对象数组，其中仅包含每个项目项目的键/值。基本上从每个项目中删除所有其他数据(包括父键“project”)。

最终结果是这样的:

var formattedJSON = [
  {
    "title":"Alpha",
    "description":"Lorem ipsum dolor sit amet, consectetur adipiscing elit",
    "city":"New York"
  },
  {
    "title":"Beta",
    "description": "Lorem ipsum dolor sit amet, consectetur adipiscing elit",
    "city":"London"
  },
  {
    "title":"Gamma",
    "description":"Lorem ipsum dolor sit amet, consectetur adipiscing elit",
    "Paris"
  }
]

我很难找到循环遍历数据并获得正确结果的方法。我知道已经发布了类似的问题，但似乎没有从内部键的嵌套键/值中创建一个新数组。

Answer 1

您可以使用 Array#map()为此，通过将数组的每个元素分配给它的 project 属性:

let initialJSON=[{"id":"01","name":"Jane","project":{"title":"Alpha","description":"Lorem ipsum dolor sit amet, consectetur adipiscing elit","city":"New York"},"dateCreated":"2018-04-28 04:11:16 UTC"},{"id":"02","name":"Sarah","project":{"title":"Beta","description":"Lorem ipsum dolor sit amet, consectetur adipiscing elit","city":"London"},"dateCreated":"2018-04-28 04:11:29 UTC"},{"id":"03","name":"Mia","project":{"title":"Gamma","description":"Lorem ipsum dolor sit amet, consectetur adipiscing elit","city":"Paris"},"dateCreated":"2018-04-28 04:11:29 UTC"}];

let result = initialJSON.map(element => element.project);

console.log(result)