c中socket编程的客户端服务器进程执行

Question

客户端代码:

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <string.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netdb.h> 

    void error(const char *msg)
    {
            perror(msg);
            exit(0);
    }


    int main(int argc, char *argv[])
    {
        int sockfd, portno, n,choice;
        struct sockaddr_in serv_addr;
        struct hostent *server;

                int buffer;

        if (argc < 3) 
        {
                fprintf(stderr,"usage %s hostname port\n", argv[0]);
                exit(0);
            }

        portno = atoi(argv[2]);
        sockfd = socket(AF_INET, SOCK_STREAM, 0);

        if (sockfd < 0) 
                error("ERROR opening socket");
                server = gethostbyname(argv[1]);

        if (server == NULL) 
        {
                fprintf(stderr,"ERROR, no such host\n");
                exit(0);
            }

            serv_addr.sin_family = AF_INET;
            bcopy((char *)server->h_addr, 
            (char *)&serv_addr.sin_addr.s_addr,server->h_length);
            serv_addr.sin_port = htons(portno);

        if (connect(sockfd,(struct sockaddr *) &serv_addr,sizeof(serv_addr)) < 0) 
                error("ERROR connecting");

        //printf("Please enter positive integer ");

        printf("Enter your choice\n1=Prime number\n2=Fibonacci number\n 3=power of 2\n");
        scanf("%d",&choice);

        if(choice==1){
        printf("Please enter positive integer ");
        scanf("%d", &buffer);
        }

            n = write(sockfd,&buffer,sizeof(buffer));

        if (n < 0) 
            error("ERROR writing to socket");
        char msg[256];
        bzero(msg, 256);

        n=read(sockfd, msg, 255);

        printf("%d %s\n",buffer, msg);

        close(sockfd);
            return 0;
}

服务器代码:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <sys/types.h> 
#include <sys/socket.h>
#include <netinet/in.h>

    void error(const char *msg)
    {
            perror(msg);
            exit(1);
    }

    int prime(int num)
    {
        int c;

        for ( c = 2 ; c <= num - 1 ; c++ )
        {
                if ( num%c == 0 )
                {
                    return 0;
                }
        }

        if ( c == num )
            return 1;

        return 0; 

    }


    int main(int argc, char *argv[])
    {
        int sockfd, newsockfd, portno;
            socklen_t clilen;
            int buffer;
            struct sockaddr_in serv_addr, cli_addr;
            int n;
        int i=1;

        if (argc < 2) 
        {
                fprintf(stderr,"ERROR, no port provided\n");
                exit(1);
            }

        sockfd = socket(AF_INET, SOCK_STREAM, 0);

        if (sockfd < 0) 
                error("ERROR opening socket");

            portno = atoi(argv[1]);
            serv_addr.sin_family = AF_INET;
            serv_addr.sin_addr.s_addr = INADDR_ANY;
            serv_addr.sin_port = htons(portno);

        if (bind(sockfd, (struct sockaddr *) &serv_addr,sizeof(serv_addr)) < 0) 
                    error("ERROR on binding");

        listen(sockfd,5);
            clilen = sizeof(cli_addr);
            newsockfd = accept(sockfd,(struct sockaddr *) &cli_addr,&clilen);

            if (newsockfd < 0) 
                error("ERROR on accept");



            n = read(newsockfd,&buffer,sizeof(buffer));

        int result= prime(buffer);

        if (n < 0) error("ERROR reading from socket");


            printf("Client's input is: %d\n",buffer);

        if(result==1)
        {

            n = write(newsockfd,"is Prime Number",18);
                if (n < 0) error("ERROR writing to socket");
        }

        else 
        {
            n = write(newsockfd,"is not Prime Number",18);
                if (n < 0) error("ERROR writing to socket");
        }





            close(newsockfd);
            close(sockfd);
            return 0; 
    }

在这个客户端-服务器进程中，服务器程序在第一次执行后终止。我想要:

1. 服务器将无限运行
2. 如果我将客户端程序保存在多台电脑上，每个客户端都能够通信，并且服务器程序不会被终止。

Answer 1

那么你显然需要循环和 fork 。