C 指针作为结构成员、分配、初始化

Question

我正在开发代数应用程序，这是代码

struct quotient
{
    int numerator;
    int denominator;
};

struct term
{
    struct quotient coefficient;
    char varname;
    struct quotient power;
};

struct function
{
    struct term* terms;
    char* operators;
    struct quotient coefficient;
    struct quotient power;
};

//Constructor Functions
struct quotient NewQuotient()
{
    struct quotient temp;
    printf("Enter the numerator\n");
    scanf("%d", &temp.numerator);
    printf("Enter the denominator\n");
    scanf("%d", &temp.denominator);
    return temp;
}

char NewVarname()
{
    char temp;
    printf("Enter the variable letter: \n");
    scanf("%c", &temp);
    return temp;
}

struct term NewTerm()
{
    //broken, won't let you enter a variable name, sets it to x by default until that's     resolved
    struct term temp;
    printf("Enter the coefficient: ");
    temp.coefficient = NewQuotient();
    printf("Enter the variable name: \n");
    temp.varname = NewVarname();
    temp.varname = 'x';
    printf("Enter the power: ");
    temp.power = NewQuotient();
    return temp;
}

void NewFunction(struct function* func, int size)
{
    //so far so good
    unsigned i;
    func->terms = (struct term*)calloc(size, sizeof(struct term));
    //loop to initialize each term
    for(i = 0; i < size; i++)
    {
        func->terms[i] = NewTerm();
    }
    return;
}

int main(){
    struct function fofx;
    NewFunction(&fofx, 2);
    DisplayFunction(&fofx, 2);
    DeleteFunction(&fofx);

    return 0;
}

这是输出:

Enter the numerator:
1
Enter the denominator:
2
Enter the numerator:
3
Enter the denominator:
4
....

等等，直到循环结束。

NewTerm 中的一半语句似乎根本没有执行，但程序似乎成功分配并初始化了一个新函数。非常感谢任何帮助，我对此感到非常困惑。我没有包含显示和删除功能，它们工作正常，但如果它们有帮助，我可以在此处添加它们。

Answer 1

您没有为 calloc 提供正确的大小，应该是 sizeof (struct term) 而不是 sizeof (int)。这可能是问题所在，具体取决于 struct term 的实际大小以及 size 的值。

关于 NewTerm 没有被调用，这可能是因为您没有调用它。