c - 如何跳过一行中的第一个字符 - C

Question

我有一个简单的程序，可以读取一行，其中包含 3 个数字。我需要跳过第一个数字，这是“产品”中的代码。

所以，我只需要读取第二个和第三个字符。

我该怎么做？

到目前为止的代码:

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

int calculate_price (number, value)
{
    int price=0;
    price= number*value;
    return price;
}

int main(void)
{
    int number, value, u,price;
    FILE  *bill, *total_price;
    bill= fopen("bill.txt","rt");
    total_price= fopen("total_price.txt","wt");

    if (bill== NULL)
    {
        printf("The file cannot be open.\nQuitting the program.\n");
        exit(1);
    }

    if (total_price== NULL)
    {
        printf("The file canno be written.\nQuitting the program.\n");
        exit(1);
    }

    while (fscanf(bill, "%d %d",&number, &value) != EOF)
    {
        u=calculate_price(number, value);
        fprintf(total_price,"The total price is %d\n", u);
    }
    printf("File created sucessfully. Check the file.\n");

}

Answer 1

int main(void)
{
    int number, value, u,price;
    int dummy; //this is a dummy var

...

while (fscanf(bill, "%d %d %d",&dummy, &number, &value) != EOF)
{
    u=calculate_price(number, value);
    fprintf(total_price,"The total price is %d\n", u);
}
printf("File created sucessfully. Check the file.\n");

编辑之前我使用了一个 char 作为虚拟变量，因为不知何故我首先误解了这个问题，但我将其更正为 int...