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C 程序跳过 Main 中的 scanf 请求

转载 作者:行者123 更新时间:2023-11-30 14:20:17 25 4
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我有以下程序:

#include <stdio.h>
#include <stdlib.h> /* for malloc */
#include <ctype.h>

struct employee
{
char first_name[10];
char last_name[10];
long id_number;
float wage;
float hours;
float overtime;
float gross;

struct employee *next;
};

/*-----------------------------------------------------------------------------*/
/* */
/* FUNCTION: print_list */
/* */
/* DESCRIPTION: This function will print the contents of a linked */
/* list. It will traverse the list from beginning to the */
/* end, printing the contents at each node. */
/* */
/* PARAMETERS: emp1 - pointer to a linked list */
/* */
/* OUTPUTS: None */
/* */
/* CALLS: None */
/* */
/*-----------------------------------------------------------------------------*/
void print_list(struct employee *emp1)
{
struct employee *tmp; /* tmp pointer value to current node */
int i = 0; /* counts the nodes printed */

/* Start a beginning of list and print out each value */
/* loop until tmp points to null (remember null is 0 or false) */
for(tmp = emp1; tmp ; tmp = tmp->next)
{
i++;

/* TODO - print other members as well */
printf("\nEmployee ID: %6d, Wage: %8.2f, Hours: %5.2f\n",tmp->id_number,
tmp->wage,tmp->hours);
}

printf("\n\nTotal Number of Employees = %d\n", i);

}

/*----------------------------------------------------------------------------*/
/* */
/* FUNCTION: main */
/* */
/* DESCRIPTION: This function will prompt the user for an employee */
/* id and wage until the user indicates they are finished. */
/* At that point, a list of id and wages will be */
/* generated. */
/* */
/* PARAMETERS: None */
/* */
/* OUTPUTS: None */
/* */
/* CALLS: print_list */
/* */
/*----------------------------------------------------------------------------*/
int main ()
{

char answer[80]; /* to see if the user wants to add more employees */
int more_data = 1; /* flag to check if another employee is to be processed */
char value; /* gets the first character of answer */

struct employee *current_ptr, /* pointer to current node */
*head_ptr; /* always points to first node */

/* Set up storage for first node */
head_ptr = (struct employee *) malloc (sizeof(struct employee));
current_ptr = head_ptr;

while (more_data)
{
/* Read in Employee ID and Hourly Wage */

printf("\nEnter employee ID: ");
scanf("%li", & current_ptr -> id_number);

printf("\nEnter employee weekly wage: ");
scanf("%f", & current_ptr -> wage);

printf("\nEnter employee weekly hours: ");
scanf("%f", & current_ptr -> hours);

printf("\nEnter First Name: ");
scanf(" %c", & current_ptr -> first_name);

printf("\nEnter Last Name: ");
scanf("%c", & current_ptr -> last_name);


printf("Would you like to add another employee? (y/n): ");
scanf("%s", answer);

/* Ask user if they want to add another employee */
if ((value = toupper(answer[0])) != 'Y')
{
current_ptr->next = (struct employee *) NULL;
more_data = 0;
}
else
{
/* set the next pointer of the current node to point to the new node */
current_ptr->next = (struct employee *) malloc (sizeof(struct employee));
/* move the current node pointer to the new node */
current_ptr = current_ptr->next;
}
} /* while */

/* print out listing of all employee id's and wages that were entered */
print_list(head_ptr);

printf("\n\nEnd of program\n");

return 0;
}

我想开始读取 First_name 和 Last_name 的 ifnormation,但是当我提示用户输入 first_name 时,我输入值,按 Enter 键,然后它会跳过 Last_name 请求。我不确定为什么会发生这种情况。

最佳答案

使用%s而不是%c来读取字符串。当您读取 %c 时,您仅获得一个字符,并将其余字符留在缓冲区中。

printf("\nEnter First Name: ");
scanf("%s", &current_ptr->first_name);

关于C 程序跳过 Main 中的 scanf 请求,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/15608329/

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