ios - 如何在 Swift 中访问结构体类型数组中的变量？

Question

如何访问数组中结构体的变量？我尝试通过打印数组本身和使用第一个索引打印数组来隔离变量，但没有输出。

taskList: [["vacuum", "20 mins", "medium"], ["take out trash", "5 mins", "low"]] // list to choose from

struct Task { //to reassign from multidimensional array
var name: String = "None"
var time: String = "None"
var materials: String = "None"
}

var newTask = Task() //creation of a new task
var taskPool = [Task]() //pool of selected tasks

newTask.name = taskList[0][0]//assign name found in another list
newTask.time = taskList[0][1]//assign time found in another list
newTask.materials = taskList[0][2]//assign priority found in another list
taskPool += [newTask]
println(taskPool)
println(taskPool[0])

Answer 1

通过这种方式您可以访问它:

var taskList = [["vacuum", "20 mins", "medium"],["take out trash", "5 mins", "low"]] // list to choose from

struct Task { //to reassign from multidimensional array
    var name: String = "None"
    var time: String = "None"
    var materials: String = "None"
}

var newTask = Task() //creation of a new task
var taskPool = [Task]() //pool of selected tasks
//
newTask.name = taskList[0][0]//assign name found in another list
newTask.time = taskList[0][1]//assign time found in another list
newTask.materials = taskList[0][2]//assign priority found in another list
taskPool += [newTask]

taskPool              // [{name "vacuum", time "20 mins", materials "medium"}]
taskPool[0].name      // "vacuum"
taskPool[0].time      // "20 mins"
taskPool[0].materials // "medium"