php无法从Swift编写的Xcode程序获取参数

Question

我无法获取从swift代码发送的参数。如果我忽略该参数，我可以获得返回结果。请帮忙。谢谢

Swift 代码:

    var url: NSURL = NSURL(string: urlPath)!
    var request = NSMutableURLRequest(URL: url)
    request.HTTPMethod = "POST"
    request.timeoutInterval = 60
    request.setValue("application/json; charset=utf-8", forHTTPHeaderField: "Content-Type")
    var searchString = ""
    var bodyData: NSString = "brandCode=BU&model=test1234"
    request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding)
    var connection:NSURLConnection = NSURLConnection(request: request, delegate: self, startImmediately: false)!

    connection.start()

<小时/>

PHP 代码:

    $brandCode=$_POST['brandCode'];
    $model=$_POST['model'];
    $cnx=odbc_connect('testODBC','testing','testing');
    $sql="select * from brand where brand='".$brandCode."' and model='".$model."'";
    $cur= odbc_exec($cnx, $sql);
    while($info = odbc_fetch_array($cur))
    {
        $resultArray[]=array($info); 
    }
    echo json_encode($resultArray);

Answer 1

尝试使用此代码

var URL: NSURL = NSURL(string: "http://example.com")
var request:NSMutableURLRequest = NSMutableURLRequest(URL:URL)
request.HTTPMethod = "POST"
var bodyData = "brandCode=BU&model=test1234"
request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding);
NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()) 
{
    (response, data, error) in
    println(NSString(data: data, encoding: NSUTF8StringEncoding))
}