c# - "run an instance in a separate Thread"最简单的方法是什么？

Question

我试图通过将每个进程(类)放入一个单独的线程来模拟分布式算法，因此它们将充当一个真正的孤立进程。这些进程应该能够相互通信。

这段代码可以证明我正在尝试做的事情:

public class Process
{
    public void Run()
    {
        Console.WriteLine("Run called from thread {0}", Thread.CurrentThread.ManagedThreadId);
    }

    public void Fnc()
    {
        Console.WriteLine("Fnc called from thread {0}", Thread.CurrentThread.ManagedThreadId);
        Thread.Sleep(1000);
    }
}

class Program
{
    static void Main()
    {
        Console.WriteLine("Main is running in thread {0}", Thread.CurrentThread.ManagedThreadId);

        Process p1 = new Process();

        var t1 = new Thread(p1.Run);
        t1.Start();


        // This should call Fnc() in t1 Thread. It should also return immediatelly not waiting for method Fnc() to finish.
        p1.Fnc();

        Console.ReadLine();
    }
}

我得到这个输出:

Main is running in thread 9
Run called from thread 10
Fnc called from thread 9

我想得到这样的东西:

Main is running in thread 9
Run called from thread 10
Fnc called from thread 10

是否可以实现这种功能？

谢谢!

Answer 1

您可以使用线程并行库:

System.Threading.Tasks.Task.Factory.StartNew( ( ) => p1.Run )
    .ContinueWith( ( t ) => p1.Fnc );

或者你创建一个小的辅助方法:

class Program
{
    private static Process p1 = new Process();
    static void Main()
    {
        Console.WriteLine("Main is running in thread {0}", Thread.CurrentThread.ManagedThreadId);

        var t1 = new Thread(Helper);
        t1.Start();
        Console.ReadLine();
    }

    private static Helper( )
    {
        p.Run();
        p.Fnc();
    }
}