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javascript - 显示和格式化嵌套的 SVG

转载 作者:行者123 更新时间:2023-11-30 14:12:24 25 4
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我正在尝试显示一个嵌套的 SVG(路径),我想操纵“内部”SVG,以便它基于“内部边界框”居中和缩放 - 比方说一个 500px^2 的正方形。

这是一个示例,但我无法理解视口(viewport)和缩放以执行我需要它执行的操作。

<!DOCTYPE html>
<html>
<head>
<style>
#svg {
background:silver;
}
path {
stroke: red;
stroke-width: 0.0001;
fill: none;
}
</style>
<script src="/scripts/snippet-javascript-console.min.js?v=1"></script>
</head>
<body>
<script src="https://maps.googleapis.com/maps/api/js?v=3&libraries=geometry"></script>
<svg id="svg" height="800" width="624" viewport="0 0 800 624" preserveAspectRatio="xMinYMin meet"></svg>
<script type="text/javascript">
function latLng2point(latLng) {

return {
x: (latLng.lng + 180) * (256 / 360),
y: (256 / 2) - (256 * Math.log(Math.tan((Math.PI / 4) + ((latLng.lat * Math.PI / 180) / 2))) / (2 * Math.PI))
};
}

function poly_gm2svg(gmPaths, fx) {

var point,
gmPath,
svgPath,
svgPaths = [],
minX = 256,
minY = 256,
maxX = 0,
maxY = 0;

for (var pp = 0; pp < gmPaths.length; ++pp) {
gmPath = gmPaths[pp], svgPath = [];
for (var p = 0; p < gmPath.length; ++p) {
point = latLng2point(fx(gmPath[p]));
minX = Math.min(minX, point.x);
minY = Math.min(minY, point.y);
maxX = Math.max(maxX, point.x);
maxY = Math.max(maxY, point.y);
svgPath.push([point.x, point.y].join(','));
}


svgPaths.push(svgPath.join(' '))


}
return {
path: 'M' + svgPaths.join(' M'),
x: minX,
y: minY,
width: maxX - minX,
height: maxY - minY
};

}

function drawPoly(node, props) {

var svg = node.cloneNode(false),
g = document.createElementNS("http://www.w3.org/2000/svg", 'g'),
path = document.createElementNS("http://www.w3.org/2000/svg", 'path');
node.parentNode.replaceChild(svg, node);
path.setAttribute('d', props.path);
g.appendChild(path);
svg.appendChild(g);
svg.setAttribute('viewBox', [props.x, props.y, props.width, props.height].join(' '));


}


function init() {

for (var i = 0; i < paths.length; ++i) {
paths[i] = google.maps.geometry.encoding.decodePath(paths[i]);
}

svgProps = poly_gm2svg(paths, function (latLng) {
return {
lat: latLng.lat(),
lng: latLng.lng()
}
});
drawPoly(document.getElementById('svg'), svgProps)
}

//array with encoded paths, will be decoded later
var paths = ["ki{eFvqfiVqAWQIGEEKAYJgBVqDJ{BHa@jAkNJw@Pw@V{APs@^aABQAOEQGKoJ_FuJkFqAo@{A}@sH{DiAs@Q]?WVy@`@oBt@_CB]KYMMkB{AQEI@WT{BlE{@zAQPI@ICsCqA_BcAeCmAaFmCqIoEcLeG}KcG}A}@cDaBiDsByAkAuBqBi@y@_@o@o@kB}BgIoA_EUkAMcACa@BeBBq@LaAJe@b@uA`@_AdBcD`@iAPq@RgALqAB{@EqAyAoOCy@AmCBmANqBLqAZkB\\iCPiBJwCCsASiCq@iD]eA]y@[i@w@mAa@i@k@g@kAw@i@Ya@Q]EWFMLa@~BYpAFNpA`Aj@n@X`@V`AHh@JfB@xAMvAGZGHIDIAWOEQNcC@sACYK[MSOMe@QKKKYOs@UYQISCQ?Q@WNo@r@OHGAGCKOQ_BU}@MQGG]Io@@c@FYNg@d@s@d@ODQAMOMaASs@_@a@SESAQDqBn@a@RO?KK?UBU\\kA@Y?WMo@Iy@GWQ_@WSSGg@AkABQB_Ap@_A^o@b@Q@o@IS@OHi@n@OFS?OI}@iAQMQGQC}@DOIIUK{@IUOMyBo@kASOKIQCa@L[|AgATWN[He@?QKw@FOPCh@Fx@l@TDLELKl@aAHIJEX@r@ZTDV@LENQVg@RkA@c@MeA?WFOPMf@Ej@Fj@@LGHKDM?_@_@iC?a@HKRIl@NT?FCHMFW?YEYGWQa@GYBiAIq@Gq@L_BHSHK|@WJETSLQZs@z@_A~@uA^U`@G\\CRB\\Tl@p@Th@JZ^bB`@lAHLXVLDP?LGFSKiDBo@d@wBVi@R]VYVE\\@`@Lh@Fh@CzAk@RSDQA]GYe@eAGWSiBAWBWBIJORK`@KPOPSTg@h@}Ad@o@F[E_@EGMKUGmAEYGMIMYKs@?a@J}@@_BD_@HQJMx@e@LKHKHWAo@UoAAWFmAH}@?w@C[YwAAc@HSNM|Ao@rA}@zAq@`@a@j@eAxAuBXQj@MXSR[b@gAFg@?YISOGaAHi@Xw@v@_@d@WRSFqARUHQJc@d@m@`A[VSFUBcAEU@WFULUPa@v@Y~@UrBc@dBI~@?l@P~ABt@N`HEjA]zAEp@@p@TrBCl@CTQb@k@dAg@jAU^KJYLK@k@A[Js@d@a@b@]RgBl@[FMAw@[]G]?m@D_@F]P[Vu@t@[TMF_@Do@E_@@q@P]PWZUZw@vAkAlAGJOj@IlAMd@OR{@p@a@d@sBpD]v@a@`Aa@n@]TODgBVk@Pe@^cBfBc@Rs@La@RSPm@|@wCpDS^Wp@QZML{@l@qBbCYd@k@lAIVCZBZNTr@`@RRHZANIZQPKDW@e@CaASU?I@YTKRQx@@\\VmALYRQLCL?v@P|@D\\GJEFKDM@OCa@COOYIGm@YMUCM@]JYr@uAx@kAt@}@jAeAPWbAkBj@s@bAiAz@oAj@m@VQlAc@VQ~@aA`Au@p@Q`AIv@MZORUV_@p@iB|AoCh@q@dAaANUNWH[N{AJ[^m@t@_Av@wA\\a@`@W`@In@Al@B^E`@Wl@u@\\[VQ\\K`@Eb@?R@dAZP@d@CRExAs@\\Yt@{@LG\\MjAATINOXo@d@kAl@_AHYBOCe@QiBCm@Fq@\\wADo@AyGEeBWuB@YHu@Tu@Lk@VcCTo@d@aA\\WJE`@G~@FP?VI\\U~@sANO`@SfAMj@U\\WjAsAXS`@UNENALBHFFL?^Ml@Uj@]b@q@RUJSPkChEc@XcAb@sA|@]PaA\\OJKNER?TDTNj@Jn@?p@OfC@ZR`B@VCV_@n@{@l@WbACv@OlABnAPl@LNNHbBBNBLFFJ@^GLg@x@i@|AMP[X}@XOJKPET?l@LhAFXp@fBDRCd@S\\_@Ps@PQ@}A]S?QDe@V]b@MR[fAKt@ErAF~CANILYDKGIKe@{@Yy@e@sB[gA[c@e@YUCU?WBUHUNQPq@`AiArAMV[^e@Zc@JQJKNMz@?r@Bb@PfAAfA@VVbADn@E`@KHSEe@SMAKDKFM\\^dDCh@m@LoAQ_@@MFOZLfBEl@QbASd@KLQBOAaAc@QAQ@QHc@v@ONMJOBOCg@c@]O[EMBKFGL?RHv@ARERGNe@h@{@h@WVGNDt@JLNFPFz@LdBf@f@PJNHPF`ADPJJJDl@I`@B^Tp@bALJNDNALIf@i@PGPCt@DNE`@Uv@[dAw@RITGRCtAARBPJLPJRZxB?VEX_@vAAR?RDNHJJBh@UnBm@h@IRDRJNNJPNbBFRJLLBLCzAmAd@Uf@Gf@?P@PFJNHPFTH`BDTHNJJJ@LG`@m@^YPER@RDPHNNJRLn@HRLN^VNPHTFX@\\UlDFb@FHh@NP@HKPsB?}ASkCQ{@[y@q@}@cA{@KOCQDa@t@{CFGJCf@Nl@ZtA~@r@p@`@h@rAxBd@rA\\fARdAPjANrB?f@AtBCd@QfBkAjJOlBChA?rBFrBNlBdAfKFzAC~@Iz@Mz@Sv@s@jBmAxBi@hAWt@Sv@Qx@O`BA`@?dAPfBVpAd@`BfBlFf@fBdA~Cr@pAz@fApBhBjAt@H?IL?FBFJLx@^lHvDvh@~XnElCbAd@pGhDbAb@nAr@`Ad@`GhDnBbAxCbBrWhNJJDPARGP_@t@Qh@]pAUtAoA`Ny@jJApBBNFLJFJBv@Hb@HBF?\\"];

init();
</script>
</body>
</html>

该示例使用经过编码的谷歌多段线,这条路径可能会发生变化 - 我想强制任何路径都在 500 像素正方形的范围内 - 居中。

关于我如何做到这一点的任何指示?我知道 SVG 在绝对定位方面有点棘手。

这是 Vanilla SVG,但我会考虑使用一些 js 库,如果它们可以更好地处理定位(有什么建议吗?)

编辑:添加我正在尝试做的模型 Example

最佳答案

据我了解,您想要一个 624*800px 的 SVG,并在其中间有一个 500*500px 的区域来绘制您的路径。为此,您可以将那个大小的嵌套 SVG 放置在您想要的位置。正如您知道外部 SVG 的大小,您可以轻松地手动计算位置。在标记中,去掉 viewBox。

对于外部 SVG,您在 xour 代码中有一些错误:属性名称是 viewBox ,对于值,宽度在高度之前:

viewBox="0 0 624 800"

稍后,将路径添加到内部 <svg> 时元素(不需要 <g>),设置它的 viewBox使用路径属性中的值。就这样。

function latLng2point(latLng) {

return {
x: (latLng.lng + 180) * (256 / 360),
y: (256 / 2) - (256 * Math.log(Math.tan((Math.PI / 4) + ((latLng.lat * Math.PI / 180) / 2))) / (2 * Math.PI))
};
}

function poly_gm2svg(gmPaths, fx) {

var point,
gmPath,
svgPath,
svgPaths = [],
minX = 256,
minY = 256,
maxX = 0,
maxY = 0;

for (var pp = 0; pp < gmPaths.length; ++pp) {
gmPath = gmPaths[pp], svgPath = [];
for (var p = 0; p < gmPath.length; ++p) {
point = latLng2point(fx(gmPath[p]));
minX = Math.min(minX, point.x);
minY = Math.min(minY, point.y);
maxX = Math.max(maxX, point.x);
maxY = Math.max(maxY, point.y);
svgPath.push([point.x, point.y].join(','));
}

svgPaths.push(svgPath.join(' '))

}
return {
path: 'M' + svgPaths.join(' M'),
x: minX,
y: minY,
width: maxX - minX,
height: maxY - minY
};
}

function drawPoly(svg, props) {

path = document.createElementNS("http://www.w3.org/2000/svg", 'path');
path.setAttribute('d', props.path);
svg.setAttribute('viewBox', [props.x, props.y, props.width, props.height].join(' '));
svg.appendChild(path);
}

function init() {

for (var i = 0; i < paths.length; ++i) {
paths[i] = google.maps.geometry.encoding.decodePath(paths[i]);
}

svgProps = poly_gm2svg(paths, function (latLng) {
return {
lat: latLng.lat(),
lng: latLng.lng()
}
});
drawPoly(document.querySelector('#svg svg'), svgProps)
}

//array with encoded paths, will be decoded later
var paths = ["ki{eFvqfiVqAWQIGEEKAYJgBVqDJ{BHa@jAkNJw@Pw@V{APs@^aABQAOEQGKoJ_FuJkFqAo@{A}@sH{DiAs@Q]?WVy@`@oBt@_CB]KYMMkB{AQEI@WT{BlE{@zAQPI@ICsCqA_BcAeCmAaFmCqIoEcLeG}KcG}A}@cDaBiDsByAkAuBqBi@y@_@o@o@kB}BgIoA_EUkAMcACa@BeBBq@LaAJe@b@uA`@_AdBcD`@iAPq@RgALqAB{@EqAyAoOCy@AmCBmANqBLqAZkB\\iCPiBJwCCsASiCq@iD]eA]y@[i@w@mAa@i@k@g@kAw@i@Ya@Q]EWFMLa@~BYpAFNpA`Aj@n@X`@V`AHh@JfB@xAMvAGZGHIDIAWOEQNcC@sACYK[MSOMe@QKKKYOs@UYQISCQ?Q@WNo@r@OHGAGCKOQ_BU}@MQGG]Io@@c@FYNg@d@s@d@ODQAMOMaASs@_@a@SESAQDqBn@a@RO?KK?UBU\\kA@Y?WMo@Iy@GWQ_@WSSGg@AkABQB_Ap@_A^o@b@Q@o@IS@OHi@n@OFS?OI}@iAQMQGQC}@DOIIUK{@IUOMyBo@kASOKIQCa@L[|AgATWN[He@?QKw@FOPCh@Fx@l@TDLELKl@aAHIJEX@r@ZTDV@LENQVg@RkA@c@MeA?WFOPMf@Ej@Fj@@LGHKDM?_@_@iC?a@HKRIl@NT?FCHMFW?YEYGWQa@GYBiAIq@Gq@L_BHSHK|@WJETSLQZs@z@_A~@uA^U`@G\\CRB\\Tl@p@Th@JZ^bB`@lAHLXVLDP?LGFSKiDBo@d@wBVi@R]VYVE\\@`@Lh@Fh@CzAk@RSDQA]GYe@eAGWSiBAWBWBIJORK`@KPOPSTg@h@}Ad@o@F[E_@EGMKUGmAEYGMIMYKs@?a@J}@@_BD_@HQJMx@e@LKHKHWAo@UoAAWFmAH}@?w@C[YwAAc@HSNM|Ao@rA}@zAq@`@a@j@eAxAuBXQj@MXSR[b@gAFg@?YISOGaAHi@Xw@v@_@d@WRSFqARUHQJc@d@m@`A[VSFUBcAEU@WFULUPa@v@Y~@UrBc@dBI~@?l@P~ABt@N`HEjA]zAEp@@p@TrBCl@CTQb@k@dAg@jAU^KJYLK@k@A[Js@d@a@b@]RgBl@[FMAw@[]G]?m@D_@F]P[Vu@t@[TMF_@Do@E_@@q@P]PWZUZw@vAkAlAGJOj@IlAMd@OR{@p@a@d@sBpD]v@a@`Aa@n@]TODgBVk@Pe@^cBfBc@Rs@La@RSPm@|@wCpDS^Wp@QZML{@l@qBbCYd@k@lAIVCZBZNTr@`@RRHZANIZQPKDW@e@CaASU?I@YTKRQx@@\\VmALYRQLCL?v@P|@D\\GJEFKDM@OCa@COOYIGm@YMUCM@]JYr@uAx@kAt@}@jAeAPWbAkBj@s@bAiAz@oAj@m@VQlAc@VQ~@aA`Au@p@Q`AIv@MZORUV_@p@iB|AoCh@q@dAaANUNWH[N{AJ[^m@t@_Av@wA\\a@`@W`@In@Al@B^E`@Wl@u@\\[VQ\\K`@Eb@?R@dAZP@d@CRExAs@\\Yt@{@LG\\MjAATINOXo@d@kAl@_AHYBOCe@QiBCm@Fq@\\wADo@AyGEeBWuB@YHu@Tu@Lk@VcCTo@d@aA\\WJE`@G~@FP?VI\\U~@sANO`@SfAMj@U\\WjAsAXS`@UNENALBHFFL?^Ml@Uj@]b@q@RUJSPkChEc@XcAb@sA|@]PaA\\OJKNER?TDTNj@Jn@?p@OfC@ZR`B@VCV_@n@{@l@WbACv@OlABnAPl@LNNHbBBNBLFFJ@^GLg@x@i@|AMP[X}@XOJKPET?l@LhAFXp@fBDRCd@S\\_@Ps@PQ@}A]S?QDe@V]b@MR[fAKt@ErAF~CANILYDKGIKe@{@Yy@e@sB[gA[c@e@YUCU?WBUHUNQPq@`AiArAMV[^e@Zc@JQJKNMz@?r@Bb@PfAAfA@VVbADn@E`@KHSEe@SMAKDKFM\\^dDCh@m@LoAQ_@@MFOZLfBEl@QbASd@KLQBOAaAc@QAQ@QHc@v@ONMJOBOCg@c@]O[EMBKFGL?RHv@ARERGNe@h@{@h@WVGNDt@JLNFPFz@LdBf@f@PJNHPF`ADPJJJDl@I`@B^Tp@bALJNDNALIf@i@PGPCt@DNE`@Uv@[dAw@RITGRCtAARBPJLPJRZxB?VEX_@vAAR?RDNHJJBh@UnBm@h@IRDRJNNJPNbBFRJLLBLCzAmAd@Uf@Gf@?P@PFJNHPFTH`BDTHNJJJ@LG`@m@^YPER@RDPHNNJRLn@HRLN^VNPHTFX@\\UlDFb@FHh@NP@HKPsB?}ASkCQ{@[y@q@}@cA{@KOCQDa@t@{CFGJCf@Nl@ZtA~@r@p@`@h@rAxBd@rA\\fARdAPjANrB?f@AtBCd@QfBkAjJOlBChA?rBFrBNlBdAfKFzAC~@Iz@Mz@Sv@s@jBmAxBi@hAWt@Sv@Qx@O`BA`@?dAPfBVpAd@`BfBlFf@fBdA~Cr@pAz@fApBhBjAt@H?IL?FBFJLx@^lHvDvh@~XnElCbAd@pGhDbAb@nAr@`Ad@`GhDnBbAxCbBrWhNJJDPARGP_@t@Qh@]pAUtAoA`Ny@jJApBBNFLJFJBv@Hb@HBF?\\"];

init();
        #svg {
background:silver;
}
path {
stroke: red;
stroke-width: 0.0001;
fill: none;
}
<script src="https://maps.googleapis.com/maps/api/js?v=3&libraries=geometry"></script>

<svg id="svg" height="800" width="624" viewBox="0 0 624 800" preserveAspectRatio="xMinYMin meet">
<svg x="62" y="150" width="500" height="500"></svg>
</svg>

关于javascript - 显示和格式化嵌套的 SVG,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54181522/

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