javascript - 如何在脚本函数中获取 var？

Question

我想获取js函数值。我怎样才能得到它们？

我使用 html 和 javascript 以及 alloy-ui

我在 chrome 开发者控制台中测试。 staY.diagrambuilder 或 staY.Y 或 make 函数名。

<script>
 var staY = YUI().use(
    'aui-diagram-builder',

    function (Y) {
var diagrambuilder = new Y.DiagramBuilder({
            availableFields: availableFields,
            boundingBox: '#diagrambuilderBB',
            srcNode: '#diagrambuilderBB',
            fields: []
        });
console.log(diagrambuilder); //i want to access variable out of this script
});
</script>

如何在 chrome 开发者控制台中获取 diagrambuilder 变量？

Answer 1

<script>
var diagrambuilder = null;
var staY = YUI().use(
    'aui-diagram-builder',

    function (Y) {
diagrambuilder = new Y.DiagramBuilder({
            availableFields: availableFields,
            boundingBox: '#diagrambuilderBB',
            srcNode: '#diagrambuilderBB',
            fields: []
        });
console.log(diagrambuilder); //i want to access variable out of this script

diagramInitialized();

});

function diagramInitialized() {
    console.log('If you are seeing this thenm diagrambuilder is available in global scope'); //it is accessible now;
    console.log(diagrambuilder); //it is accessible now;
}
</script>

这是你想要的吗？ @user9041996