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c# - 自动生成的数据网格中的日期时间转换器

转载 作者:行者123 更新时间:2023-11-30 14:01:45 25 4
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我创建了一个包含 5 列的自动生成的数据网格,其中 3 列是日期时间,另外 2 列是字符串。我需要能够从日期时间列条目的末尾删除时间。

通常我使用日期转换器,但我从中得到奇怪的结果,我猜这是因为它应用于整个数据网格,而不仅仅是日期时间列。

谁能帮我解决这个问题?有没有办法挑出日期时间列来应用转换器?

谢谢,我将在下面附上一些代码:

主页.xaml:

    <UserControl x:Class="Peppermint.Flix.UI.Views.MainPage"
xmlns:my="clr-namespace:System.Windows.Controls;assembly=System.Windows.Controls.Data"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:navigation="clr-namespace:System.Windows.Controls;assembly=System.Windows.Controls.Navigation"
xmlns:local="clr-namespace:Peppermint.Flix.UI"
mc:Ignorable="d"
d:DesignHeight="300" d:DesignWidth="400" xmlns:sdk="http://schemas.microsoft.com/winfx/2006/xaml/presentation/sdk">

<UserControl.Resources>
<local:DateTimeConverter x:Key="DateTimeConverter" />
</UserControl.Resources>

<Grid x:Name="LayoutRoot" Background="White">

<Grid.RowDefinitions>
<RowDefinition Height="0.5*" />
<RowDefinition Height="10*" />
</Grid.RowDefinitions>

<Grid x:Name="QuickNav" Grid.Row="0">

<Grid.ColumnDefinitions>
<ColumnDefinition Width="0.2*"/>
<ColumnDefinition Width="1*"/>
</Grid.ColumnDefinitions>

<Grid x:Name="ComboBox" Grid.Column="0">
<ComboBox HorizontalAlignment="Stretch" Height="20" ItemsSource="{Binding NavItems}" SelectedItem="{Binding NavItem, Mode=TwoWay}" />
</Grid>

<Grid x:Name="GoButton" Grid.Column="1">
<Button Content="Go" HorizontalAlignment="Left" Height="20" Command="{Binding GoCommand, Mode=OneTime}" />
</Grid>
</Grid>

<Grid x:Name="DataGrid" Grid.Row="1" >
<sdk:DataGrid HorizontalAlignment="Stretch" VerticalAlignment="Stretch" AutoGenerateColumns="True" ItemsSource="{Binding TransferPackages, Converter={StaticResource DateTimeConverter} }"/>
</Grid>
</Grid>
</UserControl>

MainViewModel.cs:

    public class MainViewModel : ViewModelBase
{

private string _navItem;
private TransferPackageViewModel _data;

#region Constructor
public MainViewModel()
{
GoCommand = new DelegateCommand<object>(QuickNavGo);
TransferPackages = new ObservableCollection<TransferPackageViewModel>();
NavItems = new List<string> { "QUICK NAV", "New Transfer Package" };
TransferPackages.Add(new TransferPackageViewModel { TransferPackageName = "Harry Potter 7 The Golden Amulet in 4D (12A)", CreatedBy = "Bilbo Baggins" });
TransferPackages.Add(new TransferPackageViewModel { TransferPackageName = "Harry Potter 8 The Hairy InnKeeper in 4D (12A)", CreatedBy = "Bilbo Baggins" });
TransferPackages.Add(new TransferPackageViewModel { TransferPackageName = "Harry Potter 7 The Milking the Cow in 5D (12A)", CreatedBy = "Bilbo Baggins" });

}
#endregion

public TransferPackageViewModel Data
{
get { return _data; }
set { _data = value; OnPropertyChanged("Data"); }
}

public void QuickNavGo(object obj)
{
MessageBox.Show("This will open the new Transfer Package Window");
}

public string NavItem
{
get { return _navItem; }
set { _navItem = value; OnPropertyChanged("NavItem"); }
}

public ObservableCollection<TransferPackageViewModel> TransferPackages { get; set; }
public List<string> NavItems { get; set; }
public ICommand GoCommand { get; set; }

}
}

DateTimeConverter.cs:

    public class DateTimeConverter : IValueConverter
{

public object Convert(object value, Type targetType,
object parameter, CultureInfo culture)
{
if (parameter != null)
{
string formatString = parameter.ToString();

if (!string.IsNullOrEmpty(formatString))
{
return string.Format(culture, formatString, value);
}
}

return value.ToString();
}

public object ConvertBack(object value, Type targetType,
object parameter, CultureInfo culture)
{
if (value != null)
{
return DateTime.Parse(value.ToString());
}
return value;
}
}

}

最佳答案

你可以通过像这样处理 DataGridAutoGeneratingColumn 事件来解决这个问题

<DataGrid AutoGeneratingColumn="DataGrid_AutoGeneratingColumn" HorizontalAlignment="Stretch"  VerticalAlignment="Stretch" AutoGenerateColumns="True"  ItemsSource="{Binding TransferPackages}"/>

在那种情况下做这个

private void DataGrid_AutoGeneratingColumn(object sender, System.Windows.Controls.DataGridAutoGeneratingColumnEventArgs e)
{
//your date time property
if (e.PropertyType == typeof(System.DateTime))
{
DataGridTextColumn dgtc = e.Column as DataGridTextColumn;
DateTimeConverter con = new DateTimeConverter();
(dgtc.Binding as Binding).Converter = con;
}
}

和一个简单的转换器

public class DateTimeConverter : IValueConverter
{

public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
if(value != null && value.GetType() == typeof(System.DateTime))
{
DateTime t = (DateTime) value;
return t.ToShortDateString();
}
return value;
}

public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
if (value != null)
{
return DateTime.Parse(value.ToString());
}
return value;
}
}

关于c# - 自动生成的数据网格中的日期时间转换器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7793348/

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