c# - 计算e数C#

Question

我正在尝试用那个计算 e 数

e = 1 + (1/1! + 1/2! + 1/3! + ..)

用户将在该表格上选择试验次数。 form

 int trialNumber = Convert.ToInt32(Math.Round(trialNumberForm.Value, 0));
        int factorial = trialNumber;
        float factResult = 0;

        for (int i = 1; i < trialNumber; i++)
        {

            for (int b = 1; b < i; b++) //calculates x! here.
            {
                factorial = factorial * b;


            }
           factResult = factResult + (1 / factorial);
        }
        factResult++;
        MessageBox.Show(factResult.ToString());

它会计算您选择的任何数字的结果 1!我试图将变量类型从 double 更改为 float，但这并没有解决它。如何通过我上面写的公式对数字进行操作？

Answer 1

自从

  1/(n+1)! == (1/n!)/(n+1)

你可以很容易地实现e计算

  double factResult = 1; // turn double into float if you want
  double item = 1;       // turn double into float if you want

  for (int i = 1; i < trialNumber; ++i)
    factResult += (item /= i);

  ...

  MessageBox.Show(factResult.ToString());

结果:

   trial number | e
   -------------------------------
              1 | 1
              2 | 2
              3 | 2.5
              4 | 2.666666... 
              5 | 2.708333...
             10 | 2.71828152557319
             15 | 2.71828182845823 
             20 | 2.71828182845905