javascript - 如何在 jQuery 中对具有一个共同特定属性的两个对象的值求和？

Question

我有一个像这样的对象数组:

0: {Id: "D", Inmueble: "00000021", Valexcep: 2}
1: {Id: "D", Inmueble: "00000021", Valexcep: 2}
2: {Id: "D", Inmueble: "00000023", Valexcep: 1}
3: {Id: "D", Inmueble: "00000023", Valexcep: 2}
4: {Id: "D", Inmueble: "00000024", Valexcep: 3}
5: {Id: "D", Inmueble: "00000168", Valexcep: 3}

我需要对那些具有相同“Inmueble”值的对象的“Valexcep”值求和，例如数组的前两个

我需要能够得到这个输出

0: {Id: "D", Inmueble: "00000021", Valexcep: 4}
2: {Id: "D", Inmueble: "00000023", Valexcep: 3}
4: {Id: "D", Inmueble: "00000024", Valexcep: 3}
5: {Id: "D", Inmueble: "00000168", Valexcep: 3}

这是我目前的代码

    var discount = 0;
    var inmueble = "";


    $.each(array, function(i, val) {
        if (val.Id == 'D') {
            discount += val.Valexcep;
            inmueble = val.Inmueble;
            var newObj = {
                id: val.Id,
                Inmueble: val.Inmueble
                Valexcep: val.Valexcep; 
            }               
            array.push(newObj)              
        }

    });

但没有按预期工作，

知道如何解决这个问题吗？

Answer 1

您可以通过将数组作为结果集来减少数组，并查看是否存在具有相同 Inmueble 的对象，然后更新 Valexcep，否则将新对象推送到结果集。

var data = [{ Id: "D", Inmueble: "00000021", Valexcep: 2 }, { Id: "D", Inmueble: "00000021", Valexcep: 2 }, { Id: "D", Inmueble: "00000023", Valexcep: 1 }, { Id: "D", Inmueble: "00000023", Valexcep: 2 }, { Id: "D", Inmueble: "00000024", Valexcep: 3 }, { Id: "D", Inmueble: "00000168", Valexcep: 3 }],
    result = data.reduce((r, { Id, Inmueble, Valexcep }) => {
        var temp = r.find(o => o.Inmueble === Inmueble);
        if (temp) {
            temp.Valexcep += Valexcep;
        } else {
            r.push({ Id, Inmueble, Valexcep });
        }
        return r;
    }, []);

console.log(result);

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用 Map 分组.

var data = [{ Id: "D", Inmueble: "00000021", Valexcep: 2 }, { Id: "D", Inmueble: "00000021", Valexcep: 2 }, { Id: "D", Inmueble: "00000023", Valexcep: 1 }, { Id: "D", Inmueble: "00000023", Valexcep: 2 }, { Id: "D", Inmueble: "00000024", Valexcep: 3 }, { Id: "D", Inmueble: "00000168", Valexcep: 3 }],
    result = Array.from(data
        .reduce((m, { Id, Inmueble, Valexcep }) => m.set(
            Inmueble,
            { Id, Inmueble, Valexcep: (m.has(Inmueble) ? m.get(Inmueble).Valexcep : 0) + Valexcep }
        ), new Map)
        .values()
    );

console.log(result);

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