ios - AVAudioPlayer 无法在共享类中快速工作

Question

我从单例类中调用一个方法，该方法允许播放其他类的声音，但播放器不起作用，我尝试了处理相同问题的帖子中提到的内容，但它对我不起作用，在这里是我的代码:

import Foundation
import AVFoundation
import UIKit
var soundPlayer = AVAudioPlayer()

class MySingleton: NSObject, AVAudioPlayerDelegate {
var timer = NSTimer()

   class var sharedSingleton: MySingleton {
    struct Static {
        static var onceTocken: dispatch_once_t = 0
        static var instance : MySingleton? = nil
    }
    dispatch_once(&Static.onceTocken) {
        Static.instance = MySingleton()
    }
    return Static.instance!
        }
func callTimer () {
    timer = NSTimer.scheduledTimerWithTimeInterval(0.6, target: self, selector: "repeatedSound", userInfo: nil, repeats: true)
}
func repeatedSound() {

    var repeatedSoundUrl = NSURL(fileURLWithPath:    NSBundle.mainBundle().pathForResource(prayerRepitationList[selectedCellInIndex], ofType: "mp3")!)

    soundPlayer = AVAudioPlayer(contentsOfURL: repeatedSoundUrl, error: nil)
    println("repeated url is \(repeatedSoundUrl)")
    soundPlayer.prepareToPlay()
    soundPlayer.delegate = self
    soundPlayer.play()


}
}

我尝试了varplayer:AVAudioPlayer! =零:AVAudioPlayer! = nil 但不起作用，我该如何修复它？

Answer 1

创建计时器时，您需要在选择器名称末尾添加冒号“:”，因为该方法指定了一个参数。它看起来像这样:

timer = NSTimer.scheduledTimerWithTimeInterval(0.6, target: self, selector: "repeatedSound:", userInfo: nil, repeats: true)

}

并且，由于计时器调用的方法接收计时器本身的参数，因此必须如下指定:

func repeatedSound(timer: NSTimer) {
  // your other code goes here
}

我没有尝试你的代码，但这应该有帮助。