javascript - 从稍微嵌套的数组中删除重复项后保留对象的所有键

Question

我有同样的 this question 问题，但我的对象有更多的键，例如:

[{
  id: 1
  name: "abcd",
  value: 123,
  type: "foo"
},
{
  id: 1
  name: "abcd",
  value: 321,
  type: "faa"
},
{
  id: 2
  name: "dcba",
  value: 456,
  type: "baa"
}]

我想实现这样的目标:

[{
  id: 1,
  name: "abcd",
  value: [123, 321],
  type: ["foo", "faa"]
},
{
  id: 2
  name: "dcba",
  value: [456],
  type: ["baa"]
}]

额外的键具有相同的值。

Answer 1

想法是按id分组，然后映射每组对象，从第一个对象中选择id和name，从组中的所有对象中提取所有 value 和 type，转置并压缩到另一个对象，然后合并它们。

const { pipe, groupBy, prop, values, map, converge, merge, head, pick, props, transpose, zipObj } = R

const fn = pipe(
  groupBy(prop('id')), // groupBy the id
  values, // convert the object of groups to array of groups
  map(converge(merge, [ // map each group by merging the results of...
    pipe(head, pick(['id', 'name'])), // getting the id and name from the 1st item
    pipe(map(props(['value', 'type'])), transpose, zipObj(['value', 'type'])) // extract the value and type and zipping to an object
  ]))
)

const data = [{
  id: 1,
  name: "abcd",
  value: 123,
  type: "foo"
},
{
  id: 1,
  name: "abcd",
  value: 321,
  type: "faa"
},
{
  id: 2,
  name: "dcba",
  value: 456,
  type: "baa"
}]

const result = fn(data)

console.log(result)

<script src="https://cdnjs.cloudflare.com/ajax/libs/ramda/0.26.1/ramda.js"></script>