ios - 我的 Swift 项目上的编码错误缺少预期/参数&&分隔符

Question

我的项目遇到问题，它不断请求 : 之后的预期参数类型。 & 预期分隔符 我在上面留下了对问题的评论，要求我插入它们。感谢您的帮助。

        // expected parameter type following ':' &             expectedseperator ,
        func performGetRequest(targetURL: NSURLRequest, completion: { (data, HTTPStatusCode, error) -> Void in

            if HTTPStatusCode == 200 && error == nil {

            // Convert the JSON data to a dictionary.
            let resultsDict = NSJSONSerialization.JSONObjectWithData(data!, options: nil, error: nil) as! Dictionary<NSObject, AnyObject>

            let items: AnyObject! = resultsDict["items"] as AnyObject!
            let firstItemDict = (items as! Array<AnyObject>)[0] as! Dictionary<NSObject, AnyObject>

            let snippetDict = firstItemDict["snippet"] as! Dictionary<NSObject, AnyObject>

            var desiredValuesDict: Dictionary<NSObject, AnyObject> = Dictionary<NSObject, AnyObject>()
            desiredValuesDict["title"] = snippetDict["title"]
            desiredValuesDict["description"] = snippetDict["description"]
            desiredValuesDict["thumbnail"] = ((snippetDict["thumbnails"] as! Dictionary<NSObject, AnyObject>)["default"] as! Dictionary<NSObject, AnyObject>)["url"]


            desiredValuesDict["playlistID"] = ((firstItemDict["contentDetails"] as! Dictionary<NSObject, AnyObject>)["relatedPlaylists"] as! Dictionary<NSObject, AnyObject>)["uploads"]

            self.channelsDataArray.append(desiredValuesDict)

            self.tblVideos.reloadData()

            ++self.channelIndex
            if self.channelIndex < self.desiredChannelsArray.count {
            self.getChannelDetails(useChannelIDParam)
            }
            else {
            self.viewWait.hidden = true
            }

            } else {
            println("HTTP Status Code = \(HTTPStatusCode)")
            println("Error while loading channel details: \(error)") }

            })
    }        
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

Answer 1

您似乎正在尝试调用函数 performGetRequest，但您在开头使用 func 定义它。

如果这不是您的意图，也许您正在尝试定义该函数，但您必须小心完成处理程序。您可以看到正确的做法here .

最后，这是一个 question具有相同名称和类似问题的函数。我不知道您的代码是否基于此，但查看该问题及其答案可能会澄清。