c# - Windows 窗体 PictureBox - 如何在窗体的特定区域显示图像

Question

我正在使用以下代码使用 fileDialog 在我的一个表单中打开和显示图像:

private void btnExplorer_Click(object sender, EventArgs e)
        {
            OpenFileDialog openFileDialog1 = new OpenFileDialog();

            openFileDialog1.InitialDirectory = "c:\\";
            openFileDialog1.Filter = "All files (*.*)|*.*";
            openFileDialog1.FilterIndex = 2;
            openFileDialog1.RestoreDirectory = true;

            if (openFileDialog1.ShowDialog() == DialogResult.OK)
            {
                try
                {
                    PictureBox PictureBox1 = new PictureBox();
                    PictureBox1.Image = new Bitmap(openFileDialog1.FileName);
                    // Add the new control to its parent's controls collection
                    this.Controls.Add(PictureBox1);
                }
                catch (Exception ex)
                {
                    MessageBox.Show("Error loading image" + ex.Message);
                }
            }
        }

问题是我的图像显示在表单的左上角，为此我将右下角的四分之一留了下来。我怎样才能在那里显示它？

Answer 1

正如我在评论中所说，方法如下:How to: Position Controls on Windows Forms .

PictureBox PictureBox1 = new PictureBox();
PictureBox1.Image = new Bitmap(openFileDialog1.FileName);
PictureBox1.Location = new Point(20, 100); //20 from left and 100 from top
this.Controls.Add(PictureBox1);

或事后更改:

PictureBox1.Top += 50; //increase distance from top with 50