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javascript - 尝试使用模拟器测试 Firestore 安全规则时总是出现超时错误

转载 作者:行者123 更新时间:2023-11-30 13:46:11 25 4
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我尝试使用模拟器测试 firestore 安全规则,但总是出现超时错误...如果你有同样的现象或者有解决办法请告诉我。

测试结果

启动模拟器

% firebase serve --only firestore

运行测试

% yarn test
yarn run v1.19.2
$ jest
FAIL tests/firestore.test.ts (7.123s)
Firestore Security Rule
✕ sample1 (5044ms)

● Firestore Security Rule › sample1

: Timeout - Async callback was not invoked within the 5000ms timeout specified by jest.setTimeout.Timeout - Async callback was not invoked within the 5000ms timeout specified by jest.setTimeout.Error:

30 | });
31 |
> 32 | test("sample1", async () => {
| ^
33 | const db = createAuthApp();
34 | const user = usersRef(db).doc("test");
35 | await firebase.assertSucceeds(user.set({ name: "John" }));

at new Spec (node_modules/jest-jasmine2/build/jasmine/Spec.js:116:22)
at Suite.<anonymous> (tests/firestore.test.ts:32:3)
at Object.<anonymous> (tests/firestore.test.ts:16:1)

Test Suites: 1 failed, 1 total
Tests: 1 failed, 1 total
Snapshots: 0 total
Time: 8.038s
Ran all test suites.
error Command failed with exit code 1.
info Visit https://yarnpkg.com/en/docs/cli/run for documentation about this command.

环境

※由于示例,Firestore 安全规则允许一切

■firestore.test.ts

import * as firebase from "@firebase/testing";
import * as fs from "fs";

const PROJECT_ID = "firestore-rule-test";
const RULES_PATH = "firestore.rules";

// Create Firestore app with auth
const createAuthApp = (auth?: object): firebase.firestore.Firestore => {
return firebase
.initializeTestApp({ projectId: RULES_PATH, auth: auth })
.firestore();
};

const usersRef = (db: firebase.firestore.Firestore) => db.collection("user");

describe("Firestore Security Rule", () => {
beforeAll(async () => {
await firebase.loadFirestoreRules({
projectId: PROJECT_ID,
rules: fs.readFileSync(RULES_PATH, "utf8")
});
});

afterEach(async () => {
await firebase.clearFirestoreData({ projectId: PROJECT_ID });
});

afterAll(async () => {
await Promise.all(firebase.apps().map(app => app.delete()));
});

test("sample1", async () => {
const db = createAuthApp();
const user = usersRef(db).doc("test");
await firebase.assertSucceeds(user.set({ name: "John" }));
await firebase.assertSucceeds(user.get());
});
});;

最佳答案

在你的createAuthApp()函数,您正在初始化项目 ID 为 RULES_PATH 的测试应用程序但在您的测试中,您正在使用 PROJECT_ID 的项目 ID 加载安全规则.

改变

.initializeTestApp({ projectId: RULES_PATH, auth: auth })

.initializeTestApp({ projectId: PROJECT_ID, auth: auth })

应该可以解决您的问题。

如果它不能解决问题,您可以使用 --testTimeout=<number of ms> 将 Jest 超时更改为超过 5 秒。给测试更多的时间来完成。

最后,为了清楚起见,考虑重命名 createAuthAppcreateFirestoreInstance因为“创建 Auth”意味着与 FirebaseAuth 有关类。

关于javascript - 尝试使用模拟器测试 Firestore 安全规则时总是出现超时错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59285120/

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