ios - Swift - 从 peoplePickerNavigationController 访问名称

Question

我正在尝试使用 peoplePicker 访问姓名、电话等数据，我有以下功能:

func peoplePickerNavigationController(peoplePicker: ABPeoplePickerNavigationController, didSelectPerson person: ABRecordRef) {
    let phone: ABMultiValueRef? = ABRecordCopyValue(person, kABPersonPhoneProperty)?.takeRetainedValue()
    let name: ABMultiValueRef? = ABRecordCopyValue(person, kABPersonFirstNameProperty)?.takeRetainedValue()

    if (ABMultiValueGetCount(name) > 0) {
        let indexName = 0 as CFIndex
        let name = ABMultiValueCopyValueAtIndex(name, indexName).takeRetainedValue() as! String

        print("name of selected contact = \(name)")
    } else {
        print("No name")
    }

    if (ABMultiValueGetCount(phone) > 0) {
        let indexPhone = 0 as CFIndex
        let phone = ABMultiValueCopyValueAtIndex(phone, indexPhone).takeRetainedValue() as! String

        print("phone for selected contact = \(phone)")
    } else {
        print("No phone")
    }
}

它适用于手机，但给我一个联系人姓名错误线程 1:EXC_BAD_ACCESS (code=EXC_I386_GPFLT)，为什么？

编辑:屏幕截图

解决方案:

let name = ABRecordCopyValue(person, kABPersonFirstNameProperty)?.takeRetainedValue()

    if (name as! String != "") {

        print("name of selected contact = \(name)")
    } else {
        print("No name")
    }

Answer 1

只是一个假设。

ABMultiValueGetCount接受 ABMultiValueRef! 类型的参数当你经过它时name有这种类型 ABMultiValueRef? .

在 Swift 中这不是问题，但这些函数已桥接到 C，因此让我们尝试修复此不一致问题。

请在此行

let name: ABMultiValueRef? = ABRecordCopyValue(person, kABPersonFirstNameProperty)?.takeRetainedValue()

替换?有了这个! ，如下所示:

let name: ABMultiValueRef! = ABRecordCopyValue(person, kABPersonFirstNameProperty)?.takeRetainedValue()

请告诉我它是否有效。