ios - 如何重新运行一个函数，该函数将切换字典中的变量并再次运行其自身？

Question

嘿，我有 2 个简单的字符串和数字字典。我希望能够运行一次该函数，然后再次运行它，但这次是针对 barcelonavsRealMadrid1goals2 而不是原来的。因此该函数基本上为第一个字典运行它，然后将 var goalCount 更改为第二个字典名称并自动再次运行它的 self 。看起来很简单任何帮助。谢谢!代码:

var barcelonavsRealMadrid1 = [barcelonavsRealMadrid1goals, barcelonavsRealMadrid1penaltys]

var barcelonavsRealMadrid1goals : [String : Int] = ["barcelonaGoal0":14,"RealMadridGoal1":12,"barcelonaGoal2":29,"RealMadridGoal3":30]

var barcelonavsRealMadrid1goals2 : [String : Int] = ["barcelonaGoal0":14,"RealMadridGoal1":12,"barcelonaGoal2":29,"RealMadridGoal3":30]

func run() {

        var goalCount = barcelonavsRealMadrid1goals.reduce(0, combine: {
            (initial:Int, current:(key:String, value:Int)) -> Int in
            var currentCount = initial
            print("\(current.key)\", \((current.value))", terminator:", ")

            defer {

            }
            if current.value <= 30 {
                ++currentCount // add 1 to the running total
                return currentCount
            }

            return currentCount
           // This is where i want to rerun the function but with the second dictionary now
           goalCount = barcelonavsRealMadrid1(index + 1) 
        })

就像让 barcelonavsRealMadrid1 运行第一个索引槽，然后当 func 完成第一个索引槽时运行第二个索引槽，因此基本上更改了 var 目标计数，然后重新开始

Answer 1

您可以将变量作为参数传递给函数并以此为基础。

例如(仅供引用，未测试):

var barcelonavsRealMadrid1 = [barcelonavsRealMadrid1goals, barcelonavsRealMadrid1penaltys]
var barcelonavsRealMadrid1goals : [String : Int] = ["barcelonaGoal0":14,"RealMadridGoal1":12,"barcelonaGoal2":29,"RealMadridGoal3":30]
var barcelonavsRealMadrid1goals2 : [String : Int] = ["barcelonaGoal0":14,"RealMadridGoal1":12,"barcelonaGoal2":29,"RealMadridGoal3":30]

override func viewDidLoad() {
    super.viewDidLoad()
    run()
}

func run(goal:[String : Int]?) {
    if let _goal = goal {
        var goalCount = _goal.reduce(0, combine: {
            (initial:Int, current:(key:String, value:Int)) -> Int in
            var currentCount = initial;
            print("KEY: \(current.key) VALUE: \(current.value)")

            if current.value <= 30 {
                ++currentCount // add 1 to the running total
                return currentCount
            }

            return currentCount
        })
    } else {
        var goalCount = barcelonavsRealMadrid1goals.reduce(0, combine: {
            (initial:Int, current:(key:String, value:Int)) -> Int in
            var currentCount = initial;
            print("KEY: \(current.key) VALUE: \(current.value)")

            if current.value <= 30 {
                ++currentCount // add 1 to the running total
                return currentCount
            }

            run(barcelonavsRealMadrid1goals2)
            return currentCount
        })
    }
}