gpt4 book ai didi

c# - 使用 Newtonsoft Json.NET 解析多维 JSON 数组

转载 作者:行者123 更新时间:2023-11-30 13:33:04 24 4
gpt4 key购买 nike

我有 Json 返回如下:

[{"CreatedBy":"GIS_DB","CreatedDate":"3/8/2012 10:44:00 AM","Id":39,"ModifiedBy":"","ModifiedDate":"","Name":"CF-39","StatusId":1,"TrailCoordinates":[{"CreatedBy":"GIS_DB","CreatedDate":"3/8/2012 10:44:00 AM","Id":1637,"Latitude":32.76004207,"Longitude":-97.34006853,"ModifiedBy":"","ModifiedDate":"","SortOrder":1,"TrailId":39},{"CreatedBy":"GIS_DB","CreatedDate":"3/8/2012 10:44:00 AM","Id":1638,"Latitude":32.76004333,"Longitude":-97.34012121,"ModifiedBy":"","ModifiedDate":"","SortOrder":2,"TrailId":39}]},{"CreatedBy":"GIS_DB","CreatedDate":"3/8/2012 10:44:00 AM","Id":40,"ModifiedBy":"","ModifiedDate":"","Name":"CF-40","StatusId":1,"TrailCoordinates":[{"CreatedBy":"GIS_DB","CreatedDate":"3/8/2012 10:44:00 AM","Id":3755,"Latitude":32.76034332,"Longitude":-97.3402069,"ModifiedBy":"","ModifiedDate":"","SortOrder":1,"TrailId":40},{"CreatedBy":"GIS_DB","CreatedDate":"3/8/2012 10:44:00 AM","Id":3756,"Latitude":32.76019181,"Longitude":-97.3402448,"ModifiedBy":"","ModifiedDate":"","SortOrder":2,"TrailId":40}]}]

这些是我的类(class)...

public class Trails
{
[MonoTouch.Foundation.Preserve]
public Trails(){ TrailCoord = new List<trailcoords>();}

[MonoTouch.Foundation.Preserve, JsonProperty("Name")]
public string TrailName { get; set; }

[MonoTouch.Foundation.Preserve, JsonProperty("StatusId")]
public int StatusId { get; set; }

[MonoTouch.Foundation.Preserve, JsonProperty("TrailCoordinates")]
public List<trailcoords> TrailCoord { get; set; }
// public trailcoords

public Trails (string trailname, int statusid, List<trailcoords> trailcoord)
{
TrailName = trailname;
StatusId = statusid;
TrailCoord = trailcoord;
}
}

public class trailcoords
{
[MonoTouch.Foundation.Preserve]
public trailcoords(){}
[MonoTouch.Foundation.Preserve, JsonProperty("TrailId")]
public string TrailId { get; set; }

[MonoTouch.Foundation.Preserve, JsonProperty("Latitude")]
public double Latitude { get; set; }
[MonoTouch.Foundation.Preserve, JsonProperty("Longitude")]
public double Longitude { get; set; }

public trailcoords (string trailid, double latitude, double longitude)
{
TrailId = trailid;
Latitude = latitude;
Longitude = longitude;
}
}

List<Trails> Posts = JsonConvert.DeserializeObject<List<Trails>> ( json );

因此,从这里我不确定如何访问列表中的纬度和经度项。我可以毫无问题地访问 TrailName 之类的东西,但不确定我对数组中数组中的项目做错了什么。我想添加它们,以便我可以将它们绘制为类似于我制作的结构(硬编码值)中的线条:

CLLocationCoordinate2D[] tmpTrail1 = new CLLocationCoordinate2D[]{
new CLLocationCoordinate2D(32.751531, -97.361755),
new CLLocationCoordinate2D(32.751451, -97.356625),
new CLLocationCoordinate2D(32.751500, -97.332077),
};

CLLocationCoordinate2D[] tmpTrail2 = new CLLocationCoordinate2D[] {
new CLLocationCoordinate2D(32.727353, -97.361139),
new CLLocationCoordinate2D(32.747731, -97.359896),
new CLLocationCoordinate2D(32.765735, -97.360360),
};

_trailOverlayPoints = new List<CLLocationCoordinate2D[]>();
_trailOverlayPoints.Add(tmpTrail1);
_trailOverlayPoints.Add(tmpTrail2);

最佳答案

我不会声明很多类,而是按如下方式解析 json 字符串

JArray jArr = (JArray)JsonConvert.DeserializeObject(jsonstr);
foreach (var item in jArr)
{
foreach(var subitem in item["TrailCoordinates"])
{
Console.WriteLine(subitem["Longitude"] + " " + subitem["Latitude"]);
}
}

如果monotouch支持dynamic你也可以这样写

dynamic jArr2 = JsonConvert.DeserializeObject(jsonstr);
foreach (dynamic item in jArr2)
{
foreach (var subitem in item.TrailCoordinates)
{
Console.WriteLine(subitem.Longitude + " " + subitem.Latitude);
}
}

你甚至可以使用 Linq

JArray jArr = (JArray)JsonConvert.DeserializeObject(jsonstr);
var coords = jArr
.Select(x => x["TrailCoordinates"])
.SelectMany(x=>x)
.Where(x => x["TrailId"].ToString() == "40")
.Select(x => new { Lat = double.Parse(x["Latitude"].ToString()), Lon=double.Parse(x["Longitude"].ToString()) })
.ToArray();

关于c# - 使用 Newtonsoft Json.NET 解析多维 JSON 数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9976018/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com