ios - 在 Swift 中计算两个 CLLocation 点之间的方位

Question

这个问题已经有答案了:

CLLocation Category for Calculating Bearing w/ Haversine function (8 个回答)

已关闭 8 年前。

我正在尝试在仅 swift 代码中计算两个 CLLocation 点之间的方位。我遇到了一些困难，并假设这是一个非常简单的函数。堆栈溢出似乎没有列出任何内容。

func d2r(degrees : Double) -> Double {
    return degrees * M_PI / 180.0
}

func RadiansToDegrees(radians : Double) -> Double {
    return radians * 180.0 / M_PI
}


func getBearing(fromLoc : CLLocation, toLoc : CLLocation) {

    let fLat = d2r(fromLoc.coordinate.latitude)
    let fLng = d2r(fromLoc.coordinate.longitude)
    let tLat = d2r(toLoc.coordinate.latitude)
    let tLng = d2r(toLoc.coordinate.longitude)

    var a = CGFloat(sin(fLng-tLng)*cos(tLat));
    var b = CGFloat(cos(fLat)*sin(tLat)-sin(fLat)*cos(tLat)*cos(fLng-tLng))

    return atan2(a,b)
}

我的 atan2 调用遇到有关左值 cgfloat 或其他内容的错误...

Answer 1

这是一个 Objective-C 解决方案

• CLLocation Category for Calculating Bearing w/ Haversine function

可以很容易地翻译成 Swift:

func degreesToRadians(degrees: Double) -> Double { return degrees * .pi / 180.0 }
func radiansToDegrees(radians: Double) -> Double { return radians * 180.0 / .pi }

func getBearingBetweenTwoPoints1(point1 : CLLocation, point2 : CLLocation) -> Double {

    let lat1 = degreesToRadians(degrees: point1.coordinate.latitude)
    let lon1 = degreesToRadians(degrees: point1.coordinate.longitude)

    let lat2 = degreesToRadians(degrees: point2.coordinate.latitude)
    let lon2 = degreesToRadians(degrees: point2.coordinate.longitude)

    let dLon = lon2 - lon1

    let y = sin(dLon) * cos(lat2)
    let x = cos(lat1) * sin(lat2) - sin(lat1) * cos(lat2) * cos(dLon)
    let radiansBearing = atan2(y, x)

    return radiansToDegrees(radians: radiansBearing)
}

结果类型为Double，因为所有位置坐标都是这样的存储(CLLocationDegrees 是 Double 的类型别名)。