ios - Xcode swift - 无法使用类型为 'pathForResource' 的参数列表调用 '(String!)'

Question

请帮助我修复我的代码，因为我有以下错误:

Cannot invoke 'pathForResource' with an argument list of type '(String!)'

错误出现在这行代码上:

let urlpathString:String? = NSBundle.mainBundle().pathForResource(url)

我的完整代码:

import UIKit
import AVKit
import AVFoundation
import MediaPlayer

class ViewController: UIViewController {

    let avPlayerViewControler = AVPlayerViewController()
    var avPlayer:AVPlayer?
    var videoNumber:Int!
    var url:String!

    override func viewDidLoad() {
        super.viewDidLoad()     
    }

    func playVideo() {
        switch videoNumber {
            case 1 : url="20"
            case 2 : url="10"
            default : break

            let urlpathString:String? = NSBundle.mainBundle().pathForResource(url)

            if let urlPath = urlpathString {
                let movieUrl = NSURL(fileURLWithPath: urlPath)
                self.avPlayer = AVPlayer(URL: movieUrl)
                self.avPlayerViewControler.player = self.avPlayer

            }
        }
    }

    @IBAction func Button(sender: UIButton){
        videoNumber=1
        playVideo()
    }

    @IBAction func Button2(sender: UIButton) {
        videoNumber=2
        playVideo()
    }
}

Answer 1

NSBundle 没有简单的 pathForResource 方法，至少有第二个参数，例如pathForResource:ofType:

由于您无论如何都需要 NSURL，因此请使用 URL 发布的 API，将整个 if let 表达式替换为

func playVideo() {
  switch videoNumber {
    case 1 : url="20"
    case 2 : url="10"
    default : break
  }

  if let movieUrl = NSBundle.mainBundle().URLForResource(url, withExtension: "mp4") {
     self.avPlayer = AVPlayer(URL: movieUrl)
     self.avPlayerViewControler.player = self.avPlayer
  }
}

您必须将 mp4 更改为预期的扩展名。