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swift - Swift 中的drawGlyphsForGlyphRange(显示不可见字符)。已弃用替换GlyphAtIndex

转载 作者:行者123 更新时间:2023-11-30 13:05:04 25 4
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我正在尝试使用下面的类和函数来显示不可见字符,并且它工作正常。

但是replaceGlyphAtIndex在OS X 10.11中已被弃用,我们需要使用setGlyhs()

setGlyphs(<#T##glyphs: UnsafePointer<CGGlyph>##UnsafePointer<CGGlyph>#>, properties: <#T##UnsafePointer<NSGlyphProperty>#>, characterIndexes: <#T##UnsafePointer<Int>#>, font: <#T##NSFont#>, forGlyphRange: <#T##NSRange#>)

但是我在如何将replaceGlyphAtIndex 转换为setGlyphs 方面遇到困难。任何人都可以建议我如何将下面的replaceGlyphAtIndex 转换为setGlyphs() 吗?

我尝试了以下方法,但它崩溃了。

let data = String(g).dataUsingEncoding(NSUTF8StringEncoding)
let cgG = UnsafePointer<CGGlyph>(data!.bytes)
self.setGlyphs(cgG, properties: nil, characterIndexes: UnsafePointer<Int>(bitPattern: characterIndex), font: font as! NSFont, forGlyphRange: NSMakeRange(glyphIndex, 1))

谁能告诉我上面这行代码出了什么问题吗?

class MyLayoutManager: NSLayoutManager {

override func drawGlyphsForGlyphRange(glyphsToShow: NSRange, atPoint origin: NSPoint) {
if let storage = self.textStorage {
let s = storage.string
let startIndex = s.startIndex

for glyphIndex in glyphsToShow.location ..< glyphsToShow.location + glyphsToShow.length {
let characterIndex = self.characterIndexForGlyphAtIndex(glyphIndex)
let ch = s[startIndex.advancedBy(characterIndex)]
switch ch {
case " ": //Blank Space
let attrs = storage.attributesAtIndex(characterIndex, effectiveRange: nil)
if let font = attrs[NSFontAttributeName] {
let g = font.glyphWithName("period")//("periodcentered")
self.replaceGlyphAtIndex(glyphIndex, withGlyph: g)


// let data = String(g).dataUsingEncoding(NSUTF8StringEncoding)
// let cgG = UnsafePointer<CGGlyph>(data!.bytes)
//
// self.setGlyphs(cgG, properties: nil, characterIndexes: UnsafePointer<Int>(bitPattern: characterIndex), font: font as! NSFont, forGlyphRange: NSMakeRange(glyphIndex, 1))
}
case "\n": //New Line
let attrs = storage.attributesAtIndex(characterIndex, effectiveRange: nil)
if let font = attrs[NSFontAttributeName] {
let g = font.glyphWithName("logicalnot")
self.replaceGlyphAtIndex(glyphIndex, withGlyph: g)
}
case newLineUniCodeStr:
let attrs = storage.attributesAtIndex(characterIndex, effectiveRange: nil)
if let font = attrs[NSFontAttributeName] {
let g = font.glyphWithName("logicalnot")
self.replaceGlyphAtIndex(glyphIndex, withGlyph: g)
}
default:
break
}
}
}
super.drawGlyphsForGlyphRange(glyphsToShow, atPoint: origin)
}

}

最佳答案

我找到了另一种显示字形的方法。 (在下面发布我的代码,因为它可能对其他人有用)

override func drawGlyphsForGlyphRange(glyphsToShow: NSRange, atPoint origin: NSPoint) {
if let storage = self.textStorage {
let s = storage.string
let startIndex = s.startIndex

var padding:CGFloat = 0
for glyphIndex in glyphsToShow.location ..< glyphsToShow.location + glyphsToShow.length {
let characterIndex = self.characterIndexForGlyphAtIndex(glyphIndex)
if characterIndex < s.characters.count
{
var glyphStr = ""
let ch = s[startIndex.advancedBy(characterIndex)]
switch ch {
case " ": //Blank Space
glyphStr = periodCenteredUniCodeStr
case "\n": //New Line
glyphStr = lineBreakUniCodeStr
case newLineUniCodeStr:
glyphStr = lineBreakUniCodeStr
padding += 5
default:
break
}
var glyphPoint = self.locationForGlyphAtIndex(glyphIndex)
let glyphRect = self.lineFragmentRectForGlyphAtIndex(glyphIndex, effectiveRange: nil)
if glyphStr.characters.count > 0{
glyphPoint.x = glyphPoint.x + glyphRect.origin.x
glyphPoint.y = glyphRect.origin.y
NSString(string: glyphStr).drawInRect(NSMakeRect(glyphPoint.x, glyphPoint.y, 10, 10), withAttributes: nil)
}
}else{
print("Wrong count here")
}
}

}
super.drawGlyphsForGlyphRange(glyphsToShow, atPoint: origin)
}

关于swift - Swift 中的drawGlyphsForGlyphRange(显示不可见字符)。已弃用替换GlyphAtIndex,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39488939/

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