ios - 如何以编程方式创建多个按钮和操作？

Question

我正在使用 Swift 3.0。我正在尝试生成按钮的动态网格，如何以编程方式为每个生成的按钮提供唯一标识符

let button = UIButton(type: .system)
@IBOutlet weak var attendanceView: UIView!
override func viewDidLoad() {
    super.viewDidLoad()
    var xvalue = 8;
    var yvalue = 17;
    var button = UIButton();

    for _ in 0..<5{
        for _ in 0..<5{
        button = UIButton(frame: CGRect(x: xvalue, y: yvalue, width: 50 , height: 50))
        button.backgroundColor = .red()
        button.addTarget(attendanceView, action: #selector(buttonAction), for: .touchUpInside)
        self.attendanceView.addSubview(button)
        xvalue = xvalue + 72;
        }
        xvalue=8;
        yvalue = yvalue + 60;
    }
}

func buttonAction(sender: UIButton!) {
    button.backgroundColor = UIColor.green()
}

我已经做到了这一点，但是当单击按钮时它崩溃了。

Answer 1

使用button.tag来区分按钮。 red 是 UIColor 的属性，因此您可以访问它 UIColor.red。因此，请调整您的 for 循环

for i in 0..<5 {
    for i in 0..<5 {
        button = UIButton(frame: CGRect(x: xvalue, y: yvalue, width: 50 , height: 50))
        button.backgroundColor = .red
        button.addTarget(attendanceView, action: #selector(buttonAction), for: .touchUpInside)
        button.tag = i
        self.attendanceView.addSubview(button)         
    }
}

并在buttonAction()中使用.tag:

func buttonAction(sender: UIButton!) {
    switch (sender.tag){
    case 0:
        //button 0 action
    case 1:
        //button 1 action
    case 2:
        //button 2 action
    case 3:
        //button 3 action
    case 4:
        //button 4 action
    default:
        //default
    }
}